Perimeter of quadrilateral +perimeter of curved shape=26+4pi
First you would have to do V=bh to the power of 2
B= base
H= height
Base= 62
Height. 10
Its a triangle right? So you have to divide by 2
Now its V=2bh
V=2(62)(10)
62
x62
------
3844x10=38440 divide by 2
Then that should be your answer please tell me if im wrong i would love the suport
Btw this is all by memory Thanks!
SubToPewds
Answer:
which ones do you need answered? all of them? want to help
Step-by-step explanation:
Μ = 64
<span>σ = 3.5 </span>
<span>a) </span>
<span>μ - 3σ = 53.5 </span>
<span>μ - 2σ = 57.0 </span>
<span>μ - σ = 60.5 </span>
<span>μ = 64.0 </span>
<span>μ + σ = 67.5 </span>
<span>μ + 2σ = 71.0 </span>
<span>μ + 3σ = 74.5 </span>
<span>b) </span>
<span>(71 - 64)/3.5 = 2.0 </span>
<span>z = 0.9772 </span>
<span>n = 3000*(1 - 0.9772) </span>
<span>≈ 68
Hope this helps!</span>
Answer:
5y/2x
Step-by-step explanation: check the image :) hope this helps