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kozerog [31]
3 years ago
13

Venn diagram Interpretation (4 pts)- to be completed at the end of unit 4

Mathematics
1 answer:
Murrr4er [49]3 years ago
5 0
So here’s how you would create it because it’s hard to actually give you an answer. Draw three circles that overlap eachother in the middle. Label one tennis, one football, one baseball. Put 22 in tennis, 25 in football. Put 9 where football and tennis are overlapping (but not baseball). Put 17 in the part that’s overlapping tennis and baseball together (but not football), and put 20 in the circle that’s overlapping football and baseball (not tennis). In the very middle put 6. The only part I don’t understand what to do with is the 4 who don’t like any of the sports.

I would label the whole thing, students who like sports.

If you follow this step by step you should be able to get it.
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drek231 [11]

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f(x) = x2. What is g(x)?SIf(x)= x/g(x)(2,1)-5O A.06)-()O B. g(x) = 2x2O C. g(x)-9(x)=(*)O D. g(x)= x2
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As you can see all the possible answers have the same form:

g(x)=ax^2

By looking at the picture you'll notice that the graph of g(x) has to pass through the point (2,1). Remember that the points in the graph of g(x) have the form (x,g(x)). Since (2,1) is part of the graph of g(x) then we have the following:

\begin{gathered} (2,1)=(x,g(x)) \\ x=2 \\ g(2)=1 \end{gathered}

So let's evaluate the expression for g(x) that we wrote before at x=2. This way we'll obtain an equation for the number a:

\begin{gathered} g(2)=1=a\cdot2^2 \\ 1=4a \end{gathered}

Then we can divide both sides by 4:

\begin{gathered} \frac{1}{4}=\frac{4a}{4} \\ a=\frac{1}{4} \end{gathered}

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g(x)=\frac{1}{4}x^2=(\frac{1}{2}x)^2Answer

Then the answer is option A.

3 0
11 months ago
A science teacher has a supply of 5% hydrochloric acid and a supply of 65% hydrochloric acid(HC1). How much of each solution sho
Sphinxa [80]
Assume that the amount needed from the 5% solution is x and that the amount needed from the 65% solution is y.

We are given that, the final solution should be 42 ml, this means that:
x + y = 42 ...........> equation I
This can also be written as:
x = 42-y .......> equation II

We are also given that the final concentration should be 45%, this means that:
5% x + 65% y = 45% (x+y)
0.05x + 0.65y = 0.45(x+y)


We have x+y = 42 from equation I, therefore:
0.05x + 0.65y = 0.45(42)
0.05x + 0.65y = 18.9 .........> equation III

Substitute with equation II in equation III as follows:
0.05x + 0.65y = 18.9
0.05(42-y) + 0.65y = 18.9
2.1 - 0.05y + 0.65y = 18.9
0.6y = 18.9 - 2.1
0.6y = 16.8
y = 28 ml

Substitute with y in equation II to get x as follows:
x = 42-y
x = 42 - 28
x = 14 ml

Based on the above calculations:
amount of 5% solution = x = 14 ml
amount of 65% solution = y = 28 ml
The correct choice is:
The teacher will need 14 mL of the 5% solution and 28 mL of the 65% solution.
6 0
3 years ago
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