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3 years ago

What does n equal when 11/6= n+7/9

Mathematics

2 answers:

blsea [12.9K]3 years ago

8 0

Answer: 57/54

Step-by-step explanation:

Look at the attachment

svet-max [94.6K]3 years ago

6 0

Answer:

1 1/18

Step-by-step explanation:

11/6= n+7/9

Multiply each side by 36 to get rid of the fractions (36 is the least common multiply of 6 and 9)

36 (11/6)= (n+7/9)36

6*11 = 36n +7*4

66 = 36n +28

Subtract 28 from each side

66-28 = 36n +28-28

38 = 36n

Divide each side by 36

38/36 = 36n/36

38/36 =n

1 2/36 =n

Simplifying

1 1/18 =n

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Which

Vedmedyk [2.9K]

Answer:

The answer is <u>D: lll and IV only</u>

Step-by-step explanation:

8 0

3 years ago

6⁄10 _______ 9⁄12 A. > B. ≤ C. = D.

Ivanshal [37]

6/10 is equal to 0.60
9/12 is equal to 0.75
your answer is not above for D but if D is < then that would be the correct answer :)

7 0

3 years ago

Read 2 more answers

The primary purpose of the passage is to

Charra [1.4K]

The main purpose of the passage is to describe the purpose, methods, and results of an experiment. The correct option is B.

Given a passage shown in the attached pictures.

Option B is the best answer. The first paragraph of the passage identifies and describes "Texas squash vines" (line 1), but the main focus of the passage is introduced in the first sentence of the second paragraph. The remainder of the passage focuses on describing the purpose, process, and results of recent research conducted on these Texas squash vines.

Option A is incorrect because the passage doesn’t focus on the assumptions behind a theory but rather on the way in which that theory was tested. Option C is incorrect because the passage does not contain a lot of conflicting data; most of them support the idea that there may be too many scents for the Texas squash. Option D is incorrect because the passage explains the procedures used in a study were “’very labor intensive’” (line 58) but does not present them as particularly innovative.

Hence, the primary purpose from the given passage is to describe the aim, method, and results of an experiment.

Learn more about the passage from here brainly.com/question/12555695

#SPJ4

5 0

2 years ago

(05.02 MC) A system of equations is shown below: 4x = −3y + 17 3x − 4y = −6 What is the solution to this system of equations? (−

aliina [53]

4x=-3y+17 becomes 4x+3y=17

4x+3y=17
3x-4y=-6

alrighty

elimination

muliply first equation by 4 and 2nd by 3 and add them
16x+12y=68
9x-12y=-18
add them

25x+0y=50
25x=50
idivide both sides by 25
x=2

sub back

3x-4y=-6
3(2)-4y=-6
6-4y=-6
-4y=-12
y=3

(x,y)
(2,3)

5 0

3 years ago

Read 2 more answers

1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$

Because we know $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ then:

$\frac{\delta x}{\delta r}=cos(\theta)\ and\ \frac{\delta y}{\delta r}=sin(\theta)$

We substitute in what we had:

$g_{r}(r,\theta)=f_{x}( rcos(\theta),rsin(\theta))cos(\theta)+f_{y}(rcos(\theta),rsin(\theta))sin(\theta)$

Now we put in the values $r=\sqrt{2}\ and\ \theta=\frac{\pi}{4}$ in the formula:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=f_{x}(1,1)cos(\frac{\pi}{4})+f_{y}(1,1)sin(\frac{\pi}{4})$

Because of what we supposed:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=-2cos(\frac{\pi}{4})+3sin(\frac{\pi}{4})$

And we operate to discover that:

$g_{r}(\sqrt{2},\frac{\pi}{4})=-2\frac{\sqrt{2}}{2}+3\frac{\sqrt{2}}{2}$

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}$

and this will be our answer

3 0

3 years ago