Question

Guys please answer this question best one with explanation will get brainiest and 5 start compete yourself with other

Answer 1

Answer:

${( \sin(a) + \cos(a) )}^{2} + \\ {( \sin(a) - \cos(a) )}^{2} \\ {(a + b})^{2} = {a}^{2} + 2ab + {b}^{2} \\ {(a - b})^{2} = {a}^{2} - 2ab + {b}^{2}$

${(\sin(a)+ \cos(b)})^{2} = \\{\sin(a)}^{2} + 2\sin(a)\cos(b)\\ + {\cos(b)}^{2} \\ {(\sin(a) - \cos(b)})^{2} = \\{\sin(a)}^{2} - 2\sin(a)\cos(b) + {\cos(b)}^{2}$

$2\sin(a)\cos(b) cancel :\ out$

$=2{\sin}^{2}(a) +2{\cos}^{2}(a)$