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natka813 [3]
3 years ago
10

What is an easy way to factor and equation like 2x^2-5x+3, without using the British method?

Mathematics
1 answer:
gladu [14]3 years ago
3 0

Answer:


Step-by-step explanation:

I learned this easy way to complete the sqare in the fastest way possible

First you want to get it to x^2. So the first thing you would do is divide the entire equation by 2 to get 2(x^2 -5/2x +3/2). then you do one half of b or in this case -5/2. That would make -5/4. you would put this into the factor.

2( x -5/4 +    ) ( x -5/4 -      )

Then you square that number (-5/4)

That makes 25/16. you take that number and subtract the last number or the constant, c to make 1/16. now to finish it up you square root that number. the squre root of 1/16 is 1/4. then you put that into the last part of the factor.

2( x -5/4 + 1/4) ( x -5/4 - 1/4)

Then you simplify

(x-1) 2(x-3/2)

(x-1) (2x-3)

now to make sure I am correct, I will re-multiply it out

2x^2 -5x + 3

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Which expression gives the solutions -5x+2x^2=-6x?(1pt)
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This is the concept of algebra, the solution of the given expression will be given as follows;
-5x+2x²=-6x
adding 5x on both sides we get
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Help me please !!!!!!
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Use the SF to multiply the missing information
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3 years ago
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3 years ago
Considere as seguintes afirmações: I. O inverso de 0,2 é 5. II. O triplo de \frac{2}{5} é \frac{6}{15}. III. A metade de 0,5 é \
Alex777 [14]

Answer:

I e III

Step-by-step explanation:

Recebemos declarações na questão acima para considerar.

Declaração I. O inverso de 0,2 é 5.

Matematicamente, isso é escrito como:

1 / 0,2

0,2 = 2/10

Portanto: 1 ÷ 2/10 = 1 × 10/2

= 5

Afirmação 1 é verdadeira

Declaração II.

O triplo de 2/5 é 6/15.

Triplo de 2/5 = 2/5 + 2/5 + 2/5

= 2 + 2 + 2/5

= 6/5

= 1 1/5

Declaração II é falsa

III. A metade de 0,5 é 1/5

1/2 de 0,5

= 1/2 × 0,5 = 0,25

Convertendo em fração

= 0,25 = 25/100

= 1/4

Declaração III está correta

Portanto, as afirmações verdadeiras são I e III

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