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natka813 [3]
3 years ago
10

What is an easy way to factor and equation like 2x^2-5x+3, without using the British method?

Mathematics
1 answer:
gladu [14]3 years ago
3 0

Answer:


Step-by-step explanation:

I learned this easy way to complete the sqare in the fastest way possible

First you want to get it to x^2. So the first thing you would do is divide the entire equation by 2 to get 2(x^2 -5/2x +3/2). then you do one half of b or in this case -5/2. That would make -5/4. you would put this into the factor.

2( x -5/4 +    ) ( x -5/4 -      )

Then you square that number (-5/4)

That makes 25/16. you take that number and subtract the last number or the constant, c to make 1/16. now to finish it up you square root that number. the squre root of 1/16 is 1/4. then you put that into the last part of the factor.

2( x -5/4 + 1/4) ( x -5/4 - 1/4)

Then you simplify

(x-1) 2(x-3/2)

(x-1) (2x-3)

now to make sure I am correct, I will re-multiply it out

2x^2 -5x + 3

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A line passes through the point (4, -6) and has a slope of 3/2 . Write an equation in slope-intercept form for this line.
tatyana61 [14]

A slope intercept form: y = mx + b where m = slope and b = y -intercept

A slope of 3/2 is given

So y = 3/2 x + b

To find b:

b = y - mx

A line passes through the point (4, -6)

b = -6 - (3/2)(4)

b = -6 - 6

b = - 12

Answer

Equation in  slope intercept form:  y = 3/2 x - 12


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Given the vertex of a quadratic function, find the axis of symmetry.
motikmotik

(i) The equation of the axis of symmetry is x = - 5.

(ii) The coordinates of the vertex of the parabola are (h, k) = (4, - 18). The x-value of the vertex is 4.

(iii) According to the <em>vertex</em> form of the <em>quadratic</em> equation, the parabola opens down due to <em>negative</em> lead coefficient and has a vertex at (2, 4), which is a <em>maximum</em>.  

<h3>How to analyze and interpret quadratic functions</h3>

In this question we must find and infer characteristics from three cases of <em>quadratic</em> equations. (i) In this case we must find a formula of a axis of symmetry based on information about the vertex of the parabola. Such axis passes through the vertex. Hence, the equation of the axis of symmetry is x = - 5.

(ii) We need to transform the <em>quadratic</em> equation into its <em>vertex</em> form to determine the coordinates of the vertex by algebraic handling:

y = x² - 8 · x - 2

y + 18 = x² - 8 · x + 16

y + 18 = (x - 4)²

In a nutshell, the coordinates of the vertex of the parabola are (h, k) = (4, - 18). The x-value of the vertex is 4.

(iii) Now here we must apply a procedure similar to what was in used in part (ii):

y = - 2 · (x² - 4 · x + 2)

y - 4 = - 2 · (x² - 4 · x + 2) - 4

y - 4 = - 2 · (x² - 4 · x + 4)

y - 4 = - 2 · (x - 2)²

According to the <em>vertex</em> form of the <em>quadratic</em> equation, the parabola opens down due to <em>negative</em> lead coefficient and has a vertex at (2, 4), which is a <em>maximum</em>.  

To learn more on quadratic equations: brainly.com/question/1863222

#SPJ1

5 0
1 year ago
Which of the following is NOT true of a perpendicular bisector?
kodGreya [7K]

To construct a perpendicular bisector, we have to draw two arcs using each of the endpoints as centers

<h3>What is a perpendicular bisector?</h3>

A perpendicular bisector is said to be a line that intersects the segment of another line perpendicularly and also divides it into two equal parts.

The properties of a perpendicular bisector include:

  • It divides a line segment into two equal parts
  • It makes right angles with the line segment.
  • Points in the perpendicular bisector are equal from the line of the segment.

Hence, all the mentioned properties are correct except that to construct it, we have to draw two arcs using each of the endpoints as centers.

Learn more about perpendicular bisector here:

brainly.com/question/21752287

#SPJ1

3 0
1 year ago
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