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ladessa [460]
2 years ago
6

Angle MNO is formed by segments MN and NO on the following coordinate grid:

Mathematics
2 answers:
sergiy2304 [10]2 years ago
7 0

Answer with explanation:

It is given that ,∠M NO is formed by segments MN and NO on the following coordinate grid.

Coordinate of Point M = (-1,1)

Coordinate of Point N= (-5,4)

Coordinate of Point O= (-1,4)

MN=\sqrt{(-1+5)^2+(1-4)^2}\\\\MN=\sqrt{16+9}\\\\MN=5\\\\NO=\sqrt{(-1+5)^2+(4-4)^2}\\\\NO=4\\\\MO=\sqrt{(-1+1)^2+(4-1)^2}\\\\MO=3

MO²+NO²=MN²

So,By Pythagorean Theorem, ΔM NO is right Angled Triangle having ∠ O=90°.

Now, it is given that, ∠MNO is rotated 90 degrees counterclockwise about the origin to form ∠ M′N′O′.

⇒When we rotate a Triangle either Anticlockwise or Clockwise the triangle before Rotation and Triangle after rotation will be congruent to each other.

Option D:→

 m∠ M′N′O′ = m∠M NO

Eva8 [605]2 years ago
6 0

Answer:

I am 90% sure that the answer is M'N'O' is 90*

Step-by-step explanation:

A line segment MN is shown as M = -1,1 and N= -5,4 this makes a diagonal line across the grid. Another line segment NO is shown with O as ordered pair negative 1, 4. Angle MNO is rotated 90 degrees counterclockwise about the origin to form angle M′N′O′. this is where the angles meet, Rotating the shape (or the angles) does not change the degree of the angle of the shape. I am 99% sure that an 90* angle would be formed. but im just in middle school so what do i know?

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93÷60 is 1.55

93 is 155% of 60
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The radius of a mini basketball is 4 inches. what is the volume rounded to the nearest tenth?
AVprozaik [17]

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268.08 inches3

Step-by-step explanation:

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51 m^2

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2 years ago
Read 2 more answers
Triangle abc has side lengths ab = 65, bc = 33, and ac = 56. find the radius of the circle tangent to side ac and bc and to the
lara [203]

The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.

r= 24.

<h3>What is the radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.?</h3>

Generally, the equation for side lengths AB is  mathematically given as

Triangle ABC has side lengths

Where

  • AB = 65,
  • BC = 33,
  • AC = 56.

Hence

r √ 2 · (89 √ 2/2 − r √ 2) = r(89 − 2r),

r = 89 − 65

r= 24.

In conclusion, The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.

r= 24.

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7 0
1 year ago
Give an example of each of the following or explain why you think such a set could not exist.
Oksanka [162]

Answer:

a.No

b.No

c.No

Step-by-step explanation:

a.No,Such set does not exist .A set of natural numbers is N

Every point of this set is an isolated point but no accumulation point

Accumulation point:It is defined as that point a of set Swhich every neighborhood contains infinitely many distinct point of set

(a-\epsilon,e+\epsilon)\cap S-{a}\neq\phi

Isolated point : it is defined as that point a of set S which neighborhood   does not contain any other point of set except itself

(a-\epsilon0,a+\epsilon)\cap S-{a}=\phi

Interior point of set :Let a\in S .Then a is called interior point of set when its neighborhood is a subset of set S.

a\in(a-\epsilon,e+\epsilon)\subset S

When a set is uncountable then interior point exist it is  necessary for interior points existance .

Boundary points :Let a\in S .If every non empty neighborhood of a  intersect S and complement of S.

Every member of  a set is a boundary point

b.No, such set does not exist .A non empty set with isolated point then the set have no interior points .By definition of interior point and isolated point .For example.set of natural numbers

c.No, Such set does not exist ,for example set of natural every point is an isolated point and boundary point.By definition of  boundary point and isolated point

6 0
3 years ago
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