Answer:
a. P(x = 0 | λ = 1.2) = 0.301
b. P(x ≥ 8 | λ = 1.2) = 0.000
c. P(x > 5 | λ = 1.2) = 0.002
Step-by-step explanation:
If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

a. What is the probability of selecting a carton and finding no defective pens?
This happens for k=0, so the probability is:

b. What is the probability of finding eight or more defective pens in a carton?
This can be calculated as one minus the probablity of having 7 or less defective pens.



c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?
We can calculate this as we did the previous question, but for k=5.

6x - 2 = x + 13
Subtract x
5x - 2 = 13
Add 2
5x = 15, x = 3
Solution: the number is 3
let x = a number
difference means that its subtraction
twice a number is 2x
so the equation should be
2x-5=3
add 5 to both sides
2x=8
divide both sides by 2
x=4
Answer:
Step-by-step explanation:
Combine like terms
7x^6
2x^5+5x^5= 7x^5
8x^3
-3x^2-6x^2= -9x^2
9x+2x= 11x
-5
Put back into order
7x^6+7x^5+8x^3-9x^2+11x-5
Should be D. 2x65=130-20=110