The first one is the correct answer, enjoy!
Answer:
The factored form is (sin x +2)(sin x-1)
Step-by-step explanation:
We have been given the trigonometric function ![\sin^2 x +\sinx-2](https://tex.z-dn.net/?f=%5Csin%5E2%20x%20%2B%5Csinx-2)
We can factor this by AC method. In AC method we multiply the term a and c and then write the middle term b in such a way that the sum/difference is equal to the product 'ac'
Using the method, we can write sinx as 2sinx -sinx
![\sin^2 x +2\sinx-\sin x-2](https://tex.z-dn.net/?f=%5Csin%5E2%20x%20%2B2%5Csinx-%5Csin%20x-2)
Now, we group the first two terms and the last two terms
![(\sin^2 x +2\sinx)+(-\sin x-2)](https://tex.z-dn.net/?f=%28%5Csin%5E2%20x%20%2B2%5Csinx%29%2B%28-%5Csin%20x-2%29)
Now, we take GCF from each group
![\sin x(\sin x +2)-1(\sin x+2)](https://tex.z-dn.net/?f=%5Csin%20x%28%5Csin%20x%20%2B2%29-1%28%5Csin%20x%2B2%29)
Factor out (sinx+2)
![(\sin x +2)(\sin x-1)](https://tex.z-dn.net/?f=%28%5Csin%20x%20%2B2%29%28%5Csin%20x-1%29)
Therefore, the factored form is (sin x +2)(sin x-1)
ok but what's the question? u gave us info but what's the question
All of the answer choices that you are given are incorrect. I have calculated it in all different ways and get the same thing and it is none of those. The correct answer would be -75 though.