Answer:
x = 6
x = -1
x = 1
Step-by-step explanation:
Given:
Correct equation;
P(x) = x³ - 6x² - x + 6
Computation:
x³ - 6x² - x + 6
x²(x-6)-1(x-6)
(x-6)(x²-1)
we know that;
a²-b² = (a+b)(a-b)
So,
(x-6)(x²-1)
(x-6)(x+1)(x-1)
So,
zeroes are;
x = 6
x = -1
x = 1
In proving that C is the midpoint of AB, we see truly that C has Symmetric property.
<h3>What is the proof about?</h3>
Note that:
AB = 12
AC = 6.
BC = AB - AC
= 12 - 6
=6
So, AC, BC= 6
Since C is in the middle, one can say that C is the midpoint of AB.
Note that the use of segment addition property shows: AC + CB = AB = 12
Since it has Symmetric property, AC = 6 and Subtraction property shows that CB = 6
Therefore, AC = CB and thus In proving that C is the midpoint of AB, we see truly that C has Symmetric property.
See full question below
Given: AB = 12 AC = 6 Prove: C is the midpoint of AB. A line has points A, C, B. Proof: We are given that AB = 12 and AC = 6. Applying the segment addition property, we get AC + CB = AB. Applying the substitution property, we get 6 + CB = 12. The subtraction property can be used to find CB = 6. The symmetric property shows that 6 = AC. Since CB = 6 and 6 = AC, AC = CB by the property. So, AC ≅ CB by the definition of congruent segments. Finally, C is the midpoint of AB because it divides AB into two congruent segments. Answer choices: Congruence Symmetric Reflexive Transitive
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You can use this one app it’s called Cymath it’s really helpful with these types of problems,
Answer:
The answer to your question is below
Step-by-step explanation:
Formula
Triangle's Area = 1/2 bh/2
Trapezoid's area = 1/2 (b1 + b2)h
Parallelogram's area = bh
Rectangle's area = bh
Considering the formulas, we can conclude that:
a) The first choice is true, both formulas have 1/2 in.
b) The second choice is also true, both equations are the same
c) The third choice is incorrect
d) This choice is correct, the bases are added,
e) This choice is incorrect, the sides are not added.
Another triple integral. We're integrating over the interior of the sphere
Let's do the outer integral over z. z stays within the sphere so it goes from -2 to 2.
For the middle integral we have
x is the inner integral so at this point we conservatively say its zero. That means y goes from 
and 
Similarly the inner integral x goes between 
So we rewrite the integral
Let's work on the inner one,
There's no z in the integrand, so we treat it as a constant.
So the middle integral is
I gotta go so I'll stop here, sorry.
