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8_murik_8 [283]
3 years ago
12

Good afternoon!

Mathematics
1 answer:
Vladimir [108]3 years ago
8 0

9514 1404 393

Answer:

  5) 112°

  6) 40°

Step-by-step explanation:

5) The angle E or ? is half the sum of the intercepted arcs:

  ? = (130° +94°)/2 = 112°

__

6) The angle D is half the difference of the intercepted arcs:

  ? = (135° -55°)/2 = 40°

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The National Transportation Safety Board publishes statistics on the number of automobile crashes that people in various age gro
ra1l [238]

Answer:

a) Null hypothesis:p\leq 0.12  

Alternative hypothesis:p > 0.12  

b) z_{\alpha}=1.64

c) z=\frac{0.134 -0.12}{\sqrt{\frac{0.12(1-0.12)}{1000}}}=1.362  

d) p_v =P(z>1.362)=0.0866  

e) For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12

Step-by-step explanation:

Information given

n=1000 represent the random sample selected

X=134 represent the number of young drivers ages 18 – 24 that had an accident

\hat p=\frac{134}{1000}=0.134 estimated proportion of young drivers ages 18 – 24 that had an accident

p_o=0.12 is the value that we want to verify

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic

p_v{/tex} represent the p valuePart aWe want to verify if the population proportion of young drivers, ages 18 – 24, having accidents is greater than 12%:  Null hypothesis:[tex]p\leq 0.12  

Alternative hypothesis:p > 0.12  

The statistic would be given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Part b

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.05 of the area in the right and we got:

z_{\alpha}=1.64

Part c

For this case the statistic would be given by:

z=\frac{0.134 -0.12}{\sqrt{\frac{0.12(1-0.12)}{1000}}}=1.362  

Part d

The p value can be calculated with the following probability:

p_v =P(z>1.362)=0.0866  

Part e

For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12

8 0
3 years ago
Three teachers buy prizes to put in the prize bin at school. Mrs. Maiers spends $7.68 on stickers.
SashulF [63]

Hi there! The answer to this problem would be 36.64$.

Step By Step:

So there is three teachers and they all brought something.

_____________________________________

| Mrs.Maiers  | 7.68$                                                |

| Mr.Lang       | 11.52$                                               |

| Mrs.Connor | 17.64$                                              |

______________________________________

Total Cost: 36.64

4 0
3 years ago
Margaret has $200 in her savings account. She will save $50 more dollars each week and not take any money out of the account. Wh
Ad libitum [116K]
Option one because it’s going up by 50 and it’s also showing that she’s starting with the 200$ she already had
4 0
3 years ago
1.Alan is x years old .Tom is 5 years older than Alan. Write an expression for the total of their ages.
N76 [4]

Answer:

1. 2x + 5

2. 35 students walked

3. 1:18

Step-by-step explanation:

5 0
3 years ago
Lana's little sister needs to take a bubble bath. The package says to put in a drop of bubble bath for every half gallon of wate
Stels [109]

Answer:

Lana can put 24 drops of bubble bath for her sister

Step-by-step explanation:

If package says to put in a drop of bubble bath for every half gallon of water in the bath tub.

If the bathtub can hold 12 gallons of water

There are 12÷1/2 gallon

=12×2/1

=24

It means there are 24 half gallons in the bathtub

If every half gallon of water requires a drop of the bubble bath

Then,

24 half gallons of water requires 24 drops of the bubble bath

4 0
3 years ago
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