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Gala2k [10]
3 years ago
15

Ben's living room is a rectangle measuring 10 yards by 168 inches. By how many feet does the length of the room exceed the width

?
Mathematics
1 answer:
Elena L [17]3 years ago
7 0
16ft
10*3=30
30*12=360
360-168=192
192/12=16
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which of the following gives an equation of a line that passes through the point (6 over 5, -19 over 5) and is parallel to the l
victus00 [196]
One equation for this would be

y = \frac{41}{16} x-\frac{55}{8}

We start by finding the slope between the two points:

m=\frac{y_2-y_1}{x_2-x_1}=\frac{-12-\frac{-19}{5}}{-2-\frac{6}{5}}
\\
\\=(-12+\frac{19}{5}) \div (-2-\frac{6}{5})
\\
\\=(\frac{-60}{5}+\frac{19}{5}) \div (\frac{-10}{5}-\frac{6}{5})
\\
\\=\frac{-41}{5} \div \frac{-16}{5}=\frac{-41}{5} \times \frac{-5}{16}=\frac{41}{16}

A line parallel to this one will have the same slope.  We will use point-slope form to write our equation:

y-y_1=m(x-x_1)
\\
\\y-\frac{-19}{5}=\frac{41}{16}(x-\frac{6}{5})
\\
\\y+\frac{19}{5}=\frac{41}{16}x- \frac{41}{16} \times \frac{6}{5}
\\
\\y+\frac{19}{5}=\frac{41}{16}x-\frac{246}{80}
\\
\\y+\frac{304}{80}=\frac{41}{16}x-\frac{246}{80}
\\
\\y=\frac{41}{16}x-\frac{246}{80}-\frac{304}{80}
\\
\\y=\frac{41}{16}x-\frac{550}{80}
\\
\\y=\frac{41}{16}x-\frac{55}{8}
6 0
3 years ago
Please help ?? =) ^-^
katrin2010 [14]

17 + 6 = 23

She has 23 quarters.

Each games cost 2 quarters.

23/2 = 11.5

She can play 11 games and has 1 quarter leftover.

7 0
3 years ago
Read 2 more answers
Area = 120 units squared <br> Base = 8 units <br> Length = ? (Include the units in your answer)
Vesnalui [34]

Answer:

15

Step-by-step explanation:

Okay, so we know that Base*Length=Area, so we just have to divide the area by the base, so the formula here is Area/Base=Length.

That would get us 120/8=Length,

and if we just divide 120 by 8 we get 15, so the length is 15

4 0
2 years ago
4. What's the area of the above figure, which has sides of length 6 and 8?
ANTONII [103]

Answer:

48

Step-by-step explanation:

To get the area of anything you multiply the width by the length.

6×8=48

4 0
3 years ago
What is the interquartile range of this data? 6 8 9
vladimir1956 [14]

Answer:

24

Step-by-step explanation:

Just subtract the first quartile form the third quartile.

third quartile - first quartile

32 - 8 = 24 IQR

FIRST quartile: 8

SECOND quartile: 20

THIRD quartile: 32

So the IQR is 24

Hope this helps :)

3 0
3 years ago
Read 2 more answers
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