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Otrada [13]
3 years ago
13

What is the interquartile range of this data? 6 8 9

Mathematics
2 answers:
iVinArrow [24]3 years ago
4 0
25, because you subtract quartile3(37) and quartile1(12)
vladimir1956 [14]3 years ago
3 0

Answer:

24

Step-by-step explanation:

Just subtract the first quartile form the third quartile.

third quartile - first quartile

32 - 8 = 24 IQR

FIRST quartile: 8

SECOND quartile: 20

THIRD quartile: 32

So the IQR is 24

Hope this helps :)

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Help please and simplify answer in radical form if needed
deff fn [24]

Answer:

16\sqrt{3}\:\mathrm{units^2}

Step-by-step explanation:

The area of an equilateral triangle with side length s is equal to \frac{\sqrt{3}}{4}s^2. Since the perimeter is 24 units and there are three equal sides to an equilateral triangle, each side is 24\div 3=8 units.

Substituting in this value, we get:

\frac{\sqrt{3}}{4}8^2=\frac{64\sqrt{3}}{4}=\boxed{16\sqrt{3}}

6 0
3 years ago
What is sin B ?
Neporo4naja [7]

Answer:

The answer to your question is sin B = \frac{8}{17}

Step-by-step explanation:

Sine is the trigonometric function that relates the opposite side and the hypotenuse.

In the picture, we have the hypotenuse and the adjacent side, so we must calculate the opposite side using the Pythagorean theorem.

                b² = c² - a²

                b² = 17² - 15²

                b² = 289 - 225

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Now, we can calculate the sine

               sin B = \frac{opposite side}{hypotenuse}

               sin B = \frac{8}{17}

3 0
3 years ago
Find the length of the third side. If necessary, write in simplest radical form.
pychu [463]

Answer: 84 is your answer hope this helped

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Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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(7 cm)*(10 cm) = 70 cm^2

The area is the product of length and width.
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musickatia [10]

Answer:

B

Step-by-step explanation:

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8 0
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