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stepan [7]
3 years ago
13

George is an artist. He wants to paint a background with congruent squares. If his canvas is 36 cm by 48 cm, what is the side le

ngth of the greatest square possible that George can use for his background?
Mathematics
2 answers:
Hunter-Best [27]3 years ago
7 0
12 cm as anything more you can’t fill the whole shape with squares
8_murik_8 [283]3 years ago
6 0

Answer:

it could be 1000 the answer

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A pyramid with a square base has how many faces?
mylen [45]

Answer:

It has 5 Faces. The 4 Side Faces are Triangles. The Base is a Square. It has 5 Vertices (corner points)


Step-by-step explanation:


3 0
4 years ago
!!!!SHOW WHY IT IS CORRECT PLEASEEE!!!!<br>\and please don't steal the points :(
jek_recluse [69]

Answer: Its correct because 3(2t+d) = 6t + 3d are equal.

Step-by-step explanation:

First we need to solve the equation

3( 2t+d ) = 6t + 3d              //// Do some distributive property

6t + 3d = 6t + 3d               //// Do you see it . . . They are equal to each other.

So its true.

4 0
3 years ago
Read 2 more answers
Evaluate each log without a calculator
Mrac [35]

QUESTION 1

The given logarithmic expression is

\log_4(\frac{1}{16})

We rewrite \frac{1}{16} in the index form to base 4.

This implies that;

\log_4(\frac{1}{16})=\log_4(4^{-2})

We now apply the power rule: \log_a(m^n)=n\log_a(m^n).

\log_4(\frac{1}{16})=-2\log_4(4)

Recall that logarithm of the base is 1.

\log_4(\frac{1}{16})=-2(1)

\log_4(\frac{1}{16})=-2

QUESTION 2

The given logarithm is;

\log_2(\sqrt[5]{32})

\log_2(\sqrt[5]{2^5})

This is the same as;

\log_2(2^{5\times \frac{1}{5}})

\log_2(2^{1})

\log_2(2)=1

6 0
3 years ago
= X<br> 20<br> 100<br> 60<br><br> Please help me
satela [25.4K]

Answer:

x = 100

Step-by-step explanation:

(100-40)/2

= 60/2

= 30

So it's 100

Answered by GAUTHMATH

5 0
3 years ago
3х -10 y =-70<br> 4х +9y = 63
Katena32 [7]

Answer:

(0,7)

Step-by-step explanation:

(I'm assuming you have to solve the system of equations)

3x -10y = -70

4x +9y = 63

Solving by elimination.

Eliminate x first, so we need the x-component of both equations to have the same number but opposite sign. So i'm going to multiply the first by -4 and the second by +3.

//I could have also done +3 to first and -4 to second

-4(3x -10y = -70)

3(4x +9y = 63)

-12x +40y = 280

12x +27y = 189

Add the equations //x's cancel

67y = 469

Divide both side by 67, y=7

Plug in y into any original equation to solve to x

3x - 10(7) = -70

3x -70 = -70

3x = 0

x=0

4 0
3 years ago
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