9, I believe.
4(2)+2(1)^2-(1)^3 (^ just means to the power of "exponent")
8+2-1=9
Answer:
like here x= 3 and y= -15
here, its 5 times goes in negative
now if y = 10 TO X IS 5 TIME POSITIVE HERE = 10×5 = 50
Answer:
Two answers:
22 ≥ v
OR
v ≤ 22
Step-by-step explanation:
It's the same as solving for a variable in an equality. Imagine it as 17 = v - 5 for a moment. Simplify by subtracting 5 from both sides and re-add the inequality sign. This can be easily done since we are not multiplying or dividing, just adding and subtracting.
So I’m going to solve this using algebra OK?
So what you do is take the first integer as X.
Then we know that x(the first number) + X+2(the second number) is 288 right?
So we solve that saying x+x+2=288.
So 2X+2=288
2X+2-2=288-2 right?
So 2X=286.
So x is 286/2 right?
So x is 143.
Now the first number is 143 right?
So the second number should be 143+2 so 145.
I know they are not even but these are the solutions.
I don’t think there are any consecutive even numbers that add up to 288
20 multiplied (times) 4 is equal to 80 c:
