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kolezko [41]
3 years ago
15

How can $54,000 be invested part at 8% annual simple Interest and the remainder at 10% annual simple interest so that the intere

st earned by the two accounts will be equal
Mathematics
1 answer:
Nastasia [14]3 years ago
3 0

Answer:

0.08x = $5400-0.1x Add 0.1x to both sides of the equation.

0.18x = $5400 Divide both sides by 0.18

x = $3000 and $54000-$3000 = $24000

$3,000 is invested at 8%

$2,400 is invested at 10%

Step-by-step explanation:

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3 years ago
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Norma-Jean [14]

A) Ms.Wright receive $12 as interest at the end of 1/2 year.

B)  Ms.Wright receive $24 as interest at the end of 1 year.

Step-by-step explanation:

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The rate of simple interest  = 3%

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\textrm{SIMPLE INTEREST} =  \frac{P \times R \times t}{100} \\\implies SI  = \frac{800 \times 3 \times 0.5}{100}  = 12

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