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slavikrds [6]
3 years ago
10

Determine whether the following relation represent a function​

Mathematics
1 answer:
Bogdan [553]3 years ago
8 0

Answer:

No

Step-by-step explanation:

It does not pass the vertical line test; two points have the same input and different outputs, and one input can only have one output.

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Find the value of this expression is x=-6. X2/x+3
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Answer:

4

Step-by-step explanation:

x=-6

Fill in for x

(-6)2/(-6)+3

-12/-3

=4

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Finish the following table for the given function
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It is D because us the given equation all you do is plug in the x values given on the chart  
 
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To get the right shade of paint, the paint store mixes 1 part yellow with
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6 parts yellow

Step-by-step explanation:

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3 years ago
A ball is thrown from first base to second base and then from second base to home plate. How many feet has the ball been thrown?
RSB [31]

Answer:

B. 90 + 90 √2

Step-by-step explanation:

From first base to the second base, it will travel 90 feet.

From the second base to the home plate, it will travel a longer distance.  How much?  Well, if you look at the layout of the field, you'll see that if you draw a line from second base to the home plate, you'll form two rectangular triangles, one with the 1st base, another one with the 3rd base.

The line from the 2nd base to home plate is the hypotenuse, which we can easily find by:

h²=90² + 90²

h = √(2 * 90²)

h = 90 √2

So, from second base to home plate, the ball has traveled 90 √2

Overall: 90 + 90 √2

8 0
3 years ago
(15 pts) 4. Find the solution of the following initial value problem: y"-10y'+25y = 0 with y(0) = 3 and y'(0) = 13
jolli1 [7]

Answer:

y(x)=3e^{5x}-2xe^{5x}

Step-by-step explanation:

The given differential equation is y''-10y'+25y=0

The characteristics equation is given by

r^2-10r+25=0

Finding the values of r

r^2-5r-5r+25=0\\\\r(r-5)-5(r-5)=0\\\\(r-5)(r-5)=0\\\\r_{1,2}=5

We got a repeated roots. Hence, the solution of the differential equation is given by

y(x)=c_1e^{5x}+c_2xe^{5x}...(i)

On differentiating, we get

y'(x)=5c_1e^{5x}+5c_2xe^{5x}+c_2e^{5x}...(ii)

Apply the initial condition y (0)= 3 in equation (i)

3=c_1e^{0}+0\\\\c_1=3

Now, apply the initial condition y' (0)= 13 in equation (ii)

13=5(3)e^{0}+0+c_2e^{0}\\\\13=15+c_2\\\\c_2=-2

Therefore, the solution of the differential equation is

y(x)=3e^{5x}-2xe^{5x}

5 0
3 years ago
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