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Elden [556K]
3 years ago
14

How many rows and colums in 16 divided by 112

Mathematics
1 answer:
earnstyle [38]3 years ago
4 0
The answer to this question is:0.1428571429.
Hope this helps! (:
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Which of the following equations is an example of inverse variation between variables x and y ?
Mademuasel [1]
The option C) y = 15/x

a) y = 15 x is an example of direct variation, with proportionality constant = 15

b) is an example of linear variation (it is the equation of a straight line that does not pass through the origin)

c) y = 15/x => y*x = 15 = constant which is the characteristic of an inverse relation

d) y = x/15 is an example of an inverse relation, with proportion constant = 1/15 
3 0
2 years ago
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Jaimie is 5 years older than her sisiter amy . if the sum of theier ages is 19, how old is jaimie
zalisa [80]
Jamie is 14 and Amy is 5
5 0
2 years ago
The Women's Club has sold 180 of the 360 circus tickets they need to sell. What fraction has been sold?
lukranit [14]
180/360

divide 180 top and bottom

180/180 = 1
360/180 = 2

1/2 sold is your answer

hope this helps
6 0
3 years ago
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Surface integrals using an explicit description. Evaluate the surface integral \iint_{S}^{}f(x,y,z)dS using an explicit represen
Jobisdone [24]

Parameterize S by the vector function

\vec r(x,y)=x\,\vec\imath+y\,\vec\jmath+f(x,y)\,\vec k

so that the normal vector to S is given by

\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=\left(\vec\imath+\dfrac{\partial f}{\partial x}\,\vec k\right)\times\left(\vec\jmath+\dfrac{\partial f}{\partial y}\,\vec k\right)=-\dfrac{\partial f}{\partial x}\vec\imath-\dfrac{\partial f}{\partial y}\vec\jmath+\vec k

with magnitude

\left\|\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}\right\|=\sqrt{\left(\dfrac{\partial f}{\partial x}\right)^2+\left(\dfrac{\partial f}{\partial y}\right)^2+1}

In this case, the normal vector is

\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=-\dfrac{\partial(8-x-2y)}{\partial x}\,\vec\imath-\dfrac{\partial(8-x-2y)}{\partial y}\,\vec\jmath+\vec k=\vec\imath+2\,\vec\jmath+\vec k

with magnitude \sqrt{1^2+2^2+1^2}=\sqrt6. The integral of f(x,y,z)=e^z over S is then

\displaystyle\iint_Se^z\,\mathrm d\Sigma=\sqrt6\iint_Te^{8-x-2y}\,\mathrm dy\,\mathrm dx

where T is the region in the x,y plane over which S is defined. In this case, it's the triangle in the plane z=0 which we can capture with 0\le x\le8 and 0\le y\le\frac{8-x}2, so that we have

\displaystyle\sqrt6\iint_Te^{8-x-2y}\,\mathrm dx\,\mathrm dy=\sqrt6\int_0^8\int_0^{(8-x)/2}e^{8-x-2y}\,\mathrm dy\,\mathrm dx=\boxed{\sqrt{\frac32}(e^8-9)}

5 0
3 years ago
A pair of shorts costs $36. it is on sale for 25% off . what is the final price ?
maria [59]
You just do 36*.25=9
Then 36-9=27

$27 is your final price

Hope this helps!

Please crown;)
5 0
3 years ago
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