<span>Before all let's just convert Km/s into m/s :
2.41 km/s = 2410m/s\
To solve the second part
First we have to find Vy
Vy = 2410 m/s * sin 61.5
= 2410 m/s * 0.8788
=2117.908 m/s.
When the shell reaches it's maximum height the vertical velocity component will be zero
based on that theorem let's apply linear motion equation
V = u + at
0 = 2117.908 m/s - 9.8 m/S^2 * (t)
t = 216.1130 s
As the shell has to go upward and comes back to earth the shell will require a same amount of time in order to reach earth again so the total time that shell will spend on the air will be
<span>2*t
= 432.226 s
I hope my answer has come to your help. Have a nice day ahead and may God bless you always!</span></span>
