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Aneli [31]
2 years ago
9

Which classification describes the following system of equations?

Mathematics
1 answer:
wolverine [178]2 years ago
5 0

A consistent and independent system of equations describes the given system of equations.

The consistent and independent system of equations are given below.

  • 12x+5y-3z= 36
  • x-2y+4z=3
  • 9x-10y+5z = 27

<h3>What is a consistent independent equation?</h3>

A consistent equation is a system of linear equations that is consistently unbiased when it has precisely one solution. While this is the case, the graphs of the lines within the system move at exactly one point. In inconsistent, a system of linear equations is inconsistent if it has no solutions.

Learn more about the system of equations here brainly.com/question/13729904

#SPJ10

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Whats 2(4x + 90) <br> X= 189
Sunny_sXe [5.5K]

Answer:

1692

Step-by-step explanation:

 2 (4*189 + 90)

=2 (756+90)

= 2 ×846

=1692

4 0
3 years ago
Read 2 more answers
Solve for x.<br>-4x - 76 &lt; -52<br>​
Roman55 [17]

First you add 76 to get

-4x<24

And Then you divide by -4 and sincr its a negative you flip the sign to get

x>-6

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4 0
3 years ago
Write the equation of the line perpendicular to F(x)=5 that goes through (-1, -3)
Ainat [17]

Answer:

x = -1

Step-by-step explanation:

y = 5 is a horizontal line

It's perpendicular would be a vertical line of the form:

x = a

Since it passes through (-1,-3)

a = -1

Hence line is: x = -1

3 0
3 years ago
S - 10,000 = 3,753<br><br>A. s = 13,573<br><br>B. s = 13,753<br><br>C. s = 10,375
Lesechka [4]

Answer:

B. s = 13753

Step-by-step explanation:

s - 10000 = 3753

To find value of s, add both sides by 10000

s - 10000 = 3753

   +10000    +10000

-----------------------------------

s = 13753

6 0
3 years ago
10 POINTS!!! FULL ANSWER IN STEP BY STEP FORMAT!!
Lilit [14]
After a little manipulation, the given diff'l equation will look like this:

e^y * dy = (2x + 1) * dx.
                                                             x^2
Integrating both sides, we get e^y = 2------- + x + c, or e^y = x^2 + x + c
                                                               2

Now let x=0 and y = 1, o find c:

e^1 = 0^2 + 0 + c.  So, c = e, and the solution is e^y = x^2 + x + e.
4 0
3 years ago
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