Given a cylinder with a diameter of 23 mm and a volume of 12464.27 mm3, find the area of the vertical cross-section that goes th
rough the center of the bases.
A.
172.5 mm3
B.
345 mm3
C.
690 mm3
D.
30 mm3
1 answer:
Cylinder Volume = <span><span>¼ • </span><span>π • d² • height</span></span>
<span>
12,464.27 = .25 * PI * 23^2 * height
height = </span><span>12,464.27 /</span><span> .25 * PI * 23^2 </span>
height = 12,464.27 /<span> .25 * PI * 529
</span>height = 12,464.27 / <span><span><span>415.4756284373
</span>
</span>
</span>
<span>
</span><span>height = 30 mm
The vertical cross-section would be 23 mm * 30 mm =
690 SQUARE millimeters (NOT cubed as the answer says).
answer is C
</span>
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What the other person said
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can you choose mine as the brainliest answer
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About 14.14
Step-by-step explanation:
V = 4/3pi x r^3
To find the radius, divide the diameter by 2 (1.5)
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