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Nata [24]
3 years ago
5

Given a cylinder with a diameter of 23 mm and a volume of 12464.27 mm3, find the area of the vertical cross-section that goes th

rough the center of the bases.
A.
172.5 mm3

B.
345 mm3

C.
690 mm3

D.
30 mm3
Mathematics
1 answer:
Hitman42 [59]3 years ago
3 0
Cylinder Volume = <span><span>¼ • </span><span>π • d² • height</span></span>
<span>
12,464.27 = .25 * PI * 23^2 * height

height = </span><span>12,464.27 /</span><span> .25 * PI * 23^2 </span>

height = 12,464.27 /<span> .25 * PI * 529

</span>height = 12,464.27 / <span><span><span>415.4756284373 </span> </span> </span> <span>

</span><span>height = 30 mm

The vertical cross-section would be 23 mm * 30 mm =
690 SQUARE millimeters (NOT cubed as the answer says).
answer is C

</span>
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