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qwelly [4]
3 years ago
7

How do i graph the lines when the equations aren’t in slope intercept form????

Mathematics
1 answer:
jekas [21]3 years ago
7 0

Slope-Intercept Form: y=mx+b

Standard Form: ax+by=c

Point- Slope: (y-y1)= m(x-x1)

There are multiple answers to your question-

  1. If you are only missing b(the y-intercept) but are given a set of points, plug the points into x and y and solve for b.
  2. If you are only missing the slope(m) but are given a set of points, plug the points into x and y and solve for m.
  3. If you are given the standard form/point-slope form, change the equation to slope intercept form.
  4. If you are given an complete form(there is an x and y; no missing variables), but are not sure what it is, plug in some numbers in x to find y, then graph.
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What’s the correct answer for this?
Yakvenalex [24]

Answer:

B

Step-by-step explanation:

According to the theorem, equal sides have equal angles opposite to them so AB AND AC are equal so x and y are also equal

7 0
3 years ago
15/16 divided by 20<br> 7/15 divided by 14
olga2289 [7]

Answer:

The first is 0.046 and the second is 0.033

Step-by-step explanation:

4 0
3 years ago
How do you do the last two questions?
Mashutka [201]

Answer:

P = 6200 / (1 + 5.2e^(0.0013t))

increases the fastest

Step-by-step explanation:

dP/dt = 0.0013 P (1 − P/6200)

Separate the variables.

dP / [P (1 − P/6200)] = 0.0013 dt

Multiply the left side by 6200 / 6200.

6200 dP / [P (6200 − P)] = 0.0013 dt

Factor P from the denominator.

6200 dP / [P² (6200/P − 1)] = 0.0013 dt

(6200/P²) dP / (6200/P − 1) = 0.0013 dt

Integrate.

ln│6200/P − 1│= 0.0013t + C

Solve for P.

6200/P − 1 = Ce^(0.0013t)

6200/P = 1 + Ce^(0.0013t)

P = 6200 / (1 + Ce^(0.0013t))

At t = 0, P = 1000.

1000 = 6200 / (1 + C)

1 + C = 6.2

C = 5.2

P = 6200 / (1 + 5.2e^(0.0013t))

You need to change the exponent from negative to positive.

The inflection points are where the population increases the fastest.

5 0
3 years ago
The center of the circle is at (-2,-7) and its radius is 36.
Vanyuwa [196]
Standard form for circle with radius r and center (h,k) is
(x-h)^2+(y-k)^2=r^2

r=36
center at -2,-7
(x-(-2))^2+(y-(-7))^2=36^2
(x+2)^2+(y+7)^2=1296


firts option
6 0
3 years ago
Help pls first correct answer gets brainleist ​
nevsk [136]

Answer:

18

Step-by-step explanation:

a^2 + b^2 = c^2

in this case 24 is a and 30 is c

24^2 = 576

30^2 = 900

900 - 576 = 324

the square root of 324 is 18

4 0
1 year ago
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