Answer:
I believe the answer i B
Step-by-step explanation:
I'm not 100% sure so please correct me if im wrong, sorry if i am
So the problem ask to simplify the trigonometric function in your problem and base on the expression and using the theory in simplifying trigonometric function, the answer would be letter B. 2 sec^2 theta. I hope you are satisfied with my answer and feel free to ask for more
3^2+12/(6-3)*8
3^2+12/3*8
9+12/3*8
9+4*8
9+32
41
Final answer: 41
Remember to follow pemdas, parentheses, exponents, multiplication and division, followed by addition and subtraction going from left to right.
a.) N
b.)A
c.) N
d.) S
e.) S
f.)A
g.) S
i don’t need anything, just helping you all! hope it’s correct!
When roots of polynomials occur in radical form, they occur as two conjugates.
That is,
The conjugate of (a + √b) is (a - √b) and vice versa.
To show that the given conjugates come from a polynomial, we should create the polynomial from the given factors.
The first factor is x - (a + √b).
The second factor is x - (a - √b).
The polynomial is
f(x) = [x - (a + √b)]*[x - (a - √b)]
= x² - x(a - √b) - x(a + √b) + (a + √b)(a - √b)
= x² - 2ax + x√b - x√b + a² - b
= x² - 2ax + a² - b
This is a quadratic polynomial, as expected.
If you solve the quadratic equation x² - 2ax + a² - b = 0 with the quadratic formula, it should yield the pair of conjugate radical roots.
x = (1/2) [ 2a +/- √(4a² - 4(a² - b)]
= a +/- (1/2)*√(4b)
= a +/- √b
x = a + √b, or x = a - √b, as expected.
