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loris [4]
3 years ago
7

Given f(x)= √7x and g(x) = 1/x-8 which value is in the domain of f^o g

Mathematics
1 answer:
bekas [8.4K]3 years ago
8 0

Answer: x>8

Step-by-step explanation: when we plug g(x) into f(x) we get sqrt7(1/x-8) and when you graph (as shown below) this you see that the graph has a vertical asymptote of 8 therefore the domain is x>8

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anygoal [31]
The answer is   C.99 < x < 315
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3 years ago
Read 2 more answers
HELP NOW!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!11 Water boils at 212 degrees __________ A. Ce
34kurt
<span>alright it would have been easier if u took a pic but i think its a matching prob with choices A thro F:

Water boils at 212 degrees __________
 
A. Celsius Incorrect

Water boils at 100 degrees _________

B. Kelvin Incorrect

Water boils at 373 _______

C. Thermal Equilibrium Incorrect

Temperature at which all kinetic energy stops

D. Thermal Energy Incorrect

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E. Absolute zero Incorrect

Sum of all kinetic energy and potential energy in an object's particles

F. Fahrenheit



So here are the correct matches:

</span>Water boils at 212 degrees __________F. Fahrenheit
 
Water boils at 100 degrees _________ A. Celsius

Water boils at 373 _______ B. Kelvin

Temperature at which all kinetic energy stops______E. Absolute zero 

Reached when 2 objects have the same temperature ________C. Thermal Equilibrium

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7 0
3 years ago
Will give brainlyist
Luba_88 [7]

Answer:

The 2nd one

Step-by-step explanation:

hope this helps!

8 0
3 years ago
What is the other square root of 119 + 120i?
MakcuM [25]

Answer:

\sqrt{119+120 i}=\pm (12.24+i 4.90)

Step-by-step explanation:

Given

z = 119 + 120 i

Let \sqrt{119+120 i}=p+iq

Squaring both sides

119+120 i=p^2-q^2+2ipq

Comparing real and imaginary part

Re(LHS)=Re(RHS)

119=p^2-q^2...........................(1)

comparing Im(LHS)=Im(RHS)

120=2pq

q=\frac{60}{p}

Substitute q in 1

119=p^2-(\frac{60}{p})^2

p^4-119p^2-(68)^2=0

Let x=p^2

x^2-119x-4624=0

x=\dfrac{119\pm \sqrt{119^2+4\times 4624}}{2}

x=\frac{119\pm 180.71}{2}

we take only Positive value because p^2=x

x=149.85  

p^2=149.85

thus p=\pm 12.24

q=\pm 4.90

thus,

\sqrt{119+120 i}=\pm (12.24+i 4.90)

8 0
3 years ago
Solve 4(x + 1) = 4x + 4. Would it be No solution? Or all real numbers?
arsen [322]
Pick any number. Write it in place of 'x'. If the result is a true statement, then your number is a solution of the equation. Do it again with a different number. Then do it again. Does it matter what your number is ?
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