Can someone solve this and explain?

Mathematics

1 answer:

Anarel [89]3 years ago

7 0

Answer: (y-c)/m
Reasoning:
Subtract c from both sides [ y-c=mx+c-c ]
Divide m from both sides [ (y-c)/m=mx/m ]

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Four times the cube of a number is less than the difference between forty and the number. Select the inequality that represents

tigry1 [53]

Answer:

$4x^3 < 40 - x$

Explanation:

let the number be x, now we are given that four times the cube of a number which means four multiplied by the cube of number

i.e 4 multiplied by $x^3$ is less than the difference of 40 and the number x i.e 40 - x

x is for sure less than 40 as $x^3$ is less than the difference between 40 and x so if we write x - 40 then we will obtain negative value which will be greater than $x^3$ .

So, the inequality obtained can be written as $4x^3 < 40 - x$

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Find the sum. Write your answer in simplest form. 3/7 + 2/3

Delicious77 [7]

Answer:

1 2/21

Step-by-step explanation:

We start out with:

3/7 + 2/3

In order to add them together, they must have an equal denominator. An easy way to find an equal denominator is the cross method. We divide 7 by 3 and 3 by 7, giving us a denominator of 21:

3/21 + 2/21

But what about the numerators? You do the same thing as before (multiplying by the other's denominator). Now we have:

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We add both together (the denominator stays the same) and we get 23. 23/21 is correct but not in simplest form. We remove 21 from the numerator (because it is a whole) and finally get:

1 2/21!

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