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Ne4ueva [31]
3 years ago
14

Can someone solve this and explain?

Mathematics
1 answer:
Anarel [89]3 years ago
7 0
Answer: (y-c)/m
Reasoning:
Subtract c from both sides [ y-c=mx+c-c ]
Divide m from both sides [ (y-c)/m=mx/m ]
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Jeffery is a spelunker. He explores caves. Jeffery has been collecting data on the growth of stalactites over a period of years.
user100 [1]

Answer:

3.12

Step-by-step explanation:

4 0
2 years ago
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The time required to drive a fixed distance varies inversely as the speed. It takes 40 hr at a speed of 10 km/h to drive a fixed
patriot [66]

Answer:

50 hours

Step-by-step explanation:

Given data

Time=40hr

Speed=10km/hr

Let us find the fixed distance first

Speed= distance/Time

10= distance/40

distance= 10*40

distance= 400miles

Now our speed= 8km/h

hence the time is

8= 400/time

time= 400/8

time=50 hours

Hence the time is 50 hours

3 0
2 years ago
If f(x) = 3x + 2, what is f(5)?
emmasim [6.3K]

Answer:

17

Step-by-step explanation:

f(x) = 3x + 2

Let x=5

f(5) = 3*5 + 2

Multiply first

    = 15+2

Then add

    = 17

6 0
2 years ago
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Solve pls |2c+7|-3&gt;4<br> :(
kotegsom [21]

Answer:

E

Step-by-step explanation:

2c + 7 > 0

2c > -7

c > -7/2

If c < -7/2

-2c -7 -3 > 4

-2c > 14

c < -7

if c > -7/2

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4 0
2 years ago
Given: PRST is a square
xxTIMURxx [149]

Answer:

(1-\sqrt{2})a^2

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a

Thus,

MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a

Consider isosceles triangle MSC. In this triangle

MS=MC=(\sqrt{2}-1)a.

The area of this triangle is

A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}

Consider right triangle PTS. The area of this triangle is

A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2

5 0
3 years ago
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