3 years ago

Can someone solve this and explain?

Mathematics

1 answer:

Anarel [89]3 years ago

7 0

Answer: (y-c)/m
Reasoning:
Subtract c from both sides [ y-c=mx+c-c ]
Divide m from both sides [ (y-c)/m=mx/m ]

You might be interested in

How do i solve my math problem (5 carry 3 on top) carry 3 on top again

kvasek [131]

The answer will be 11. Hope it help!

7 0

3 years ago

Read 2 more answers

Solve for x in this inequality: -13 < 3x – 7 < 5

Katyanochek1 [597]

-13 < 3x – 7 < 5

Add 7 to all 3 terms;

-6 <3x<12

Divide all 3 terms by 3:

-2<x<4

3 0

2 years ago

-2x+4y= 12 3x+7y= 18 last one greatly appreciated

LenaWriter [7]

Value of x is $\frac{-6}{13}\\$ and y is $\frac{36}{13}$

Solution set is ( $\frac{-6}{13}\\$ , $\frac{36}{13}$ )

Step-by-step explanation:

We need to solve the system of equations given.

$-2x+4y=12\\3x+7y= 18$

Solving

Let:

$-2x+4y=12\,\,eq(1)\\3x+7y=18\,\,eq(2)$

Multiply eq(1) by 3 and eq(2) by 2 and add both

$-6x+12y=36\\6x+14y=36\\-------\\26y=72\\y=\frac{72}{26}\\y=\frac{36}{13}$

Putting value of y in equation 1

$-2x+4y=12\\-2x+4(\frac{36}{13})=12\\-2x+\frac{144}{13}=12\\-2x=12-\frac{144}{13}\\-2x=\frac{12*13-144}{13}\\-2x=\frac{12}{13}\\x=\frac{-6}{13}\\$

So, value of x is $\frac{-6}{13}\\$ and y is $\frac{36}{13}$

Solution set is ( $\frac{-6}{13}\\$ , $\frac{36}{13}$ )

Keywords: System of equations

Learn more about system of equations at:

#learnwithBrainly

7 0

3 years ago

assume x ≥ 0 is an integrable random variable with differentiable c.d.f. f . show that e[max{0, t − x }]

Nesterboy [21]

The answer would be c which is equal to x or t-x equals 4 or the answer

3 0

1 year ago

Identify each equation as exponential growth or exponential decay. 1) y= 112(1.32)x

svetoff [14.1K]

The answer is Exponential decay

6 0

3 years ago