All categories

3 years ago

15 points plz help

Mathematics

1 answer:

crimeas [40]3 years ago

5 0

Answer:

(+ 50,+ 11) are the points of the equilibrium point.

Step-by-step explanation:

demand is a negative line.

supply is a positive line.

You might be interested in

Analyze the problem and complete the statements.

NARA [144]

Answer:

I know this problem is an

✔ equation

because it has an equals sign.

The t is the

✔ variable

The negative sign is the

✔ operation

The 7 and the 8 are both

✔ constants

Step-by-step explanation: i took the test :( crying cuz im bouta fail

6 0

2 years ago

We can measure. waves with instruments

lana [24]

Answer:

Yes, we can measure waves with instruments. We can also use math.

8 0

3 years ago

Describe the behavior of the function ppp around its vertical asymptote at x=-2x=−2x, equals, minus, 2.

insens350 [35]

Answer:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

Step-by-step explanation:

Given

$p(x) = \frac{x^2-2x-3}{x+2}$ -- Missing from the question

Required

The behavior of the function around its vertical asymptote at $x = -2$

$p(x) = \frac{x^2-2x-3}{x+2}$

Expand the numerator

$p(x) = \frac{x^2 + x -3x - 3}{x+2}$

Factorize

$p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}$

Factor out x + 1

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

$x -> -2^{-}$ Say x = -3

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

$p(-3) = \frac{(-3-3)(-3+1)}{-3+2} = \frac{-6 * -2}{-1} = \frac{+12}{-1} = -12$

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

$x->-2^{-}, p(x)->-\infty$

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that: $x>-2$

Say x = -2.1

$p(-2.1) = \frac{(-2.1-3)(-2.1+1)}{-2.1+2} = \frac{-5.1 * -1.1}{-0.1} = \frac{+5.61}{-0.1} = -56.1$

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

$x->-2^{+}, p(x)->-\infty$

So, the behavior is:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

6 0

3 years ago

Consider and encode the following problem. The salt has been stolen! Well, it was found that the culprit was either the Caterpil

GenaCL600 [577]

The caterpillar ate the salt

3 0

3 years ago

Pythagorean theorem digital escape, can you find the length and area and type the correct code?

matrenka [14]

Answer:

A=13825

Step-by-step explanation:

5 0

2 years ago