N = 0
string temp;
if wordset[0] != wordset[1] then {
n = n + 1
}
temp = wordset[0]
for i = 1 to wordset.length - 2 do {
if wordset[i] != temp AND wordset[i] != wordset[i + 1] then {
n = n + 1
}
temp = wordset[i]
}
}
Answer:
I don't know what language you want this in, but I will do it in c++. Let me know if you want it in another language.
if (userNum1 < 0) {
cout << "userNum1 is negative" << endl;
}
else if (userNum2 > 10 {
userNum2 = 0;
} else {
cout << "userNum2 is less than or equal to 10";
}
I believe data carries radio waves
Answer:
Net Monthly Income = $3,535.67
Explanation:
Given:
GMI = $4,666.67
Total Monthly Deductions = $1,131
Find:
Net Monthly Income
Computation:
Net Monthly Income = GMI - Total Monthly Deductions
Net Monthly Income = $4,666.67 - $1,131
Net Monthly Income = $3,535.67
it is globe because I want a successful the all people
