Change the display property of each hyperlink to block.
Given the following word addresses: 3, 180, 43, 2,191, 88, 190, 14, 181, 44, 186, 253
professor190 [17]
Answer:
A. index bits = 2, tag bits = 2, block offset bits = 1, it is a miss.
B. index bits = 2, tag bits = 1, block offset bits = 0, it is a hit
C. the miss rate is 0
Explanation:
a. number of blocks = 12
number of blocks per set = 3
number of set = number of blocks / number of blocks per set = 12/3 = 4
word size = 24
block size = 2
the block offset =
block size
=
2 = 1
the index bits =
number of set =
4 = 2
the tag bits = (
word size) - offset - index = (
24) -2 - 1 = 5 -2 - 1 = 2
b. word size = 8
block size = 1
the block offset =
block size
=
1 = 0
the index bits =
number of set =
4 = 2
the tag bits = (
word size) - offset - index = (
8) -2 - 1 = 3 - 0- 2= 1
list1 = [12500, 35000, 12000, 40000, 55000,60000]
print(sum(list1)/len(list1))
We take the sum of all the elements in the list and divide the sum by the quantity of the elements. You can put however many elements in this list and you'll always get the average using the algorithm above.
It will help you present data with concise statements.