Let T be the taco, B the burrito, MP the mexican pizza, R the rice, and N the beans.
For the main course we can have the first three.
----- T
------ B
-------MP
Each main course comes with the two sides. So an R branch and a B branch go to each of the taco, burrito, or pizza.
-----T---------R or N.
We expand it to
--------T-----------R
---------------------N
And we repeat it for the rest.
Thus, the tree diagram is
----- T --------R
-----------------N
-----B---------R
-----------------N
----MP--------R
----------------N
Answer:
Step-by-step explanation:
i need indivdual prices to make an equation for the proper answer.
Answer: ∠Z ≅ ∠G and XZ ≅ FG or ∠Z ≅ ∠G and XY ≅ FE are the additional information could be used to prove that ΔXYZ ≅ ΔFEG using ASA or AAS.
Step-by-step explanation:
Given: ΔXYZ and ΔEFG such that ∠X=∠F
To prove they are congruent by using ASA or AAS conruency criteria
we need only one angle and side.
1. ∠Z ≅ ∠G(angle) and XZ ≅ FG(side)
so we can apply ASA such that ΔXYZ ≅ ΔFEG.
2. ∠Z ≅ ∠G (angle)and ∠Y ≅ ∠E (angle), we need one side which is not present here.∴we can not apply ASA such that ΔXYZ ≅ ΔFEG.
3. XZ ≅ FG (side) and ZY ≅ GE (side), we need one angle which is not present here.∴we can not apply ASA such that ΔXYZ ≅ ΔFEG.
4. XY ≅ EF(side) and ZY ≅ FG(side), not possible.
5. ∠Z ≅ ∠G(angle) and XY ≅ FE(side),so we can apply ASA such that
ΔXYZ ≅ ΔFEG.
Answer:
Step-by-step explanation:
The experimental probability is based on what already happened.
So we see that both of them found a total of 11 + 3 + 36 + 40 + 134 = 224 coins.
The coins that are worth MORE THAN 10 cents are 11 quarters and 3 fifty-cent pieces (we exclude dimes because we want MORE THAN 10 cents, NOT 10 cents exactly).
So 11 + 3 = 14 coins are worth MORE THAN 10.
So the probability of finding one worth more than 10 cents next is 14/224 = 1/16
