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9966 [12]
3 years ago
5

Can someone help me identify the pairs of parallel lines

Mathematics
1 answer:
alexandr1967 [171]3 years ago
8 0
F and g are parallel lines because they never intersect with each other.
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Look at the figure, . Find the values of ​x and y. x = 5, y = 7 x = 6, y = 8 x = 6, y = 9 x = 7, y = 10
Colt1911 [192]

Answer:

x = 6, y = 9

Step-by-step explanation:

One of the properties of a parallelogram is

The diagonals bisect each other, hence

2x = y + 3 → (1)

2y = 3x → (2)

Rearrange (1) in terms of y by subtracting 3 from both sides

y = 2x - 3 → (3)

Substitute y = 2x - 3 into (2)

2(2x - 3) = 3x ← distribute left side

4x - 6 = 3x ( add 6 to both sides )

4x = 3x + 6 ( subtract 3x from both sides )

x = 6

Substitute x = 6 into (3) for value of y

y = (2 × 6) - 3 = 12 - 3 = 9

Hence x = 6 and y = 9

5 0
3 years ago
A leaf fell into a river and traveled 140 meters in 4 minutes how many meters did the leaf travel per minute ​
Alekssandra [29.7K]

Answer:

The answer is 35

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Five thousand tickets are sold at​ $1 each for a charity raffle. Tickets are to be drawn at random and monetary prizes awarded a
aksik [14]

Answer:

the expected value of this raffle if you buy 1​ ticket = -0.65

Step-by-step explanation:

Given that :

Five thousand tickets are sold at​ $1 each for a charity raffle

Tickets are to be drawn at random and monetary prizes awarded as​ follows: 1 prize of ​$500​, 3 prizes of ​$300​, 5 prizes of ​$50​, and 20 prizes of​ $5.

Thus; the amount and the corresponding probability can be computed as:

Amount                            Probability

$500 -$1 = $499                1/5000

$300 -$1 = $299                3/5000

$50 - $1 = $49                     5/5000

$5 - $1 = $4                      20/5000

-$1                                   1- 29/5000 = 4971/5000

The expected value of the raffle if 1 ticket is being bought is  as follows:

E(x) = \sum x  * P(x)

E(x) = (499 * \dfrac{1}{5000} + 299 *\dfrac{3}{5000} + 49 *\dfrac{5}{5000} + 4 * \dfrac{20}{5000}  + (-1 * \dfrac{4971}{5000} ))

E(x) = (0.0998 + 0.1794+0.049 + 0.016  + (-0.9942 ))

E(x) = (0.3442 -0.9942 )

\mathbf{E(x) = -0.65}

Thus; the expected value of this raffle if you buy 1​ ticket = -0.65

7 0
3 years ago
Can someone please help me and fast I'm stuck
vovikov84 [41]

Answer:

3 5/8

Step-by-step explanation:

6 4/8 - 2 7/8 = 4 -3/8 = 3 5/8

8 0
2 years ago
Read 2 more answers
(Compound Amount and Compound Interest)
Igoryamba

ok done...........................

6 0
2 years ago
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