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3 years ago

Share 160 sweets in the ratio 8:12

Mathematics

1 answer:

katrin [286]3 years ago

5 0

let's divide the whole by the sum of its ratios, namely let's 160 ÷ (8+12), and then distribute accordingly.

$\bf \textit{160 at 8:12 ratio}\qquad \qquad \cfrac{8\cdot \frac{160}{8+12}}{12\cdot \frac{160}{8+12}}\implies \cfrac{8(8)}{12(8)}\implies \cfrac{64}{96}$

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Answer: 21

Step-by-step explanation:

9 + 10 = 21

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3 years ago

A company tests the life of its rechargeable batteries over six months of use. They test how long a battery will last after a fu

jonny [76]

Answer:

18.6 months

Step-by-step explanation:

Given that :

Best fit line from scatterplot :

y=-12.05x +224.26

x = Number of month

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When battery is dead completely ; charge =0, y = 0

y = -12.05x + 224.26

0 = - 12.05x + 224.26

12.05x = 224.26

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3 years ago

36.25= 45.5% of ____

aev [14]

Answer:

36.25 is equal to the 45.5% of 79.67

Step-by-step explanation:

To solve this you just have to find the value that represents the 100%.

To do this, you can use the Rule of Three that allows you to solve problems of proportions.

In this case, you know that the 45.5% of the magnitude <em>X </em>is 36.25, now you have to find the value which corresponds to the 100%.

Mathematically it will be:

$\frac{X}{36.25} =\frac{100}{45.5}$

Then you have to solve the equation to find <em>X</em>:

$X=\frac{100}{45.5}*36.25$

And finally, the answer is:

$X=79.67$

7 0

3 years ago

In which quadrant does the following ordered pair lie?

nlexa [21]

The answer would be B, ||

6 0

3 years ago

Read 2 more answers

Two random samples of 40 students were drawn independently from two populations of students. Assume their aptitude tests are nor

dybincka [34]

Answer:

b. Do not reject the null hypothesis

Step-by-step explanation:

Given that two random samples of 40 students were drawn independently from two populations of students. Assuming equal variances

we have the following data.

Sample 1

Mean:

Standard deviation:

Sample size:

Sample 2

Mean:

Standard deviation:

Sample size:

$H_0: \bar x_1=\bar x_2\\H_a: \bar x_1\neq \bar x_2$

Difference -3.000

Standard error 1.681

95% CI -6.3462 to 0.3462

t-statistic -1.785

DF 78

Significance level P = 0.0782

Since p value >0.05,

b. Do not reject the null hypothesis

7 0

3 years ago