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Dmitriy789 [7]
3 years ago
9

. You are sitting on a beach watching the waves roll in. In 12 seconds, 6 waves roll by. What is the period of the waves (7)? Wh

at is their frequency (O? 17. An AM radio station broadcasts at a frequency of 660 kHz. (note that k means 1000). Since radio waves move at the same speed as light waves, what is the wavelength of this radio wave?
Physics
1 answer:
Andrew [12]3 years ago
7 0

Answer:

Explanation:

6 waves in 12 seconds

The period of a wave is defined as the time taken by the wave to complete one oscillations.

Here, 6 waves are completed in 12 seconds

So, one wave is completed in 2 seconds

So, the period of the wave is 2 second.

frequency is defined as the number of waves completed in one second. It is the reciprocal of period of the wave.

frequency = 1 / 2 = 0.5 Hertz

Let the wavelength is λ.

f = 660  kHz = 660000 Hz

the relation for the wave speed and the wavelength and the frequency is given by

v = f λ

where v is the speed of wave = 3 x 10^8 m/s

So, 3 x 10^8 = 660000 x λ

λ = 454.55 m

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Doubly ionized lithium Li2+ (Z = 3) and triply ionized beryllium Be3+ (Z = 4) each emit a line spectrum. For a certain series of
EleoNora [17]

Answer:

tex]\lambda_{Be}[/tex] = 22.78 nm

Explanation:

Bohr's model for the hydrogen atom has been used by other atoms with a single electric charge by changing the number of charges by the charge of the new atom (atomic number)

      E_{n}= k e² / 2a₀ (1 /n²)

      ao = h'² / k m e²               h' = h/2πi

For another atom with a single electron in the last layer

      a₀ ’= h’² / k m (Ze)²  

      a₀ ’= a₀ / Z²

Therefore, when replacing in the equation

      E_{n} = - Z²  Eo/n²

     E₀ = 13,606 eV

The transition occurs when the electron stops from one level to another

         E_{n} -  E_{m} = Z² E₀ (1 / n² - 1 / m²) = Z² ΔE

Let's relate this expression to the wavelength

       c = λ f

      E = h f

      E = h c /λ

      h c / λ = Z² ΔE

     λ = 1 / Z² (hc / ΔE)

     λ = 1 / Z² λ_hydrogen

Let's apply this last equation to our case

Lithium Z = 3

     E_{n} = - 9 Eo / n²

     

      40.5 10-9 = 1/9 λ_hydrogen

Beryllium Z = 4

      λ = 1/16 λ_hydrogen

Let's write our two equations is and solve

     40.5 10-9 = 1/9 λ_hydrogen

    tex]\lambda_{Be}[/tex] = 1/ 16 λ_hydrogen

      40.5 10⁻⁹ = 1/9 (16 \lambda_{Be} )

    tex]\lambda_{Be}[/tex] = 40.5 9/16

  tex]\lambda_{Be}[/tex] = 22.78 nm

6 0
3 years ago
A certain ideal gas has molar heat capacity at constant volume CV. A sample of this gas initially occupies a volume V0 at pressu
ANTONII [103]

Answer:

Explanation:

The processes are described on the image attached below. The isobaric process consists of an horizontal line, the adiabatic expansion is described by a polytropic curve:

P_{2} \cdot V_{2}^{\gamma} = P_{3} \cdot V_{3}^{\gamma}

Where:

\gamma = \frac{c_{p}}{c_{v}}

\gamma = 1 + \frac{R}{c_{v}}

Final pressure is:

P_{3} = P_{2}\cdot \left(\frac{V_{2}}{V_{3}}  \right)^{\gamma}

P_{3} = P_{o}\cdot \left(\frac{1}{2}\right)^{\gamma}

P_{3} = \frac{P_{o}}{2^{\gamma}}

8 0
3 years ago
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