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SpyIntel [72]
3 years ago
11

The following questions consist of a statement and a reason .Answer these questions selecting the appropriate options given belo

w:
A)Both S and R are true and R is the correct explanation of the S
B)Both S and R are true but R is not the correct explanation
C)S is true but R is false
D) S is false but R is true.

(S-statement ,R-reason )

1)S-Injury caused by a moving car imore severe than the injury caused by a moving bicycle.
R-Inertia of motion is more for car

2) S-An object may appear moving for one person and stationary for some other
R-Reference point in both cases are different
Physics
1 answer:
Mamont248 [21]3 years ago
4 0

Answer:

<em><u>1)A)</u></em>

<em><u>1)A)2)A)</u></em>

<h3><em><u>Hope it helps you </u></em><em><u>♡</u></em><em><u>♡</u></em></h3>

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a bullet moving with a velocity of 100m/s pierce a block of wood and moves out with a velocityof 10 m/s.if the thickness of the
erma4kov [3.2K]

The emerging velocity of the bullet is <u>71 m/s.</u>

The bullet of mass <em>m</em> moving with a velocity <em>u</em>  has kinetic energy. When it pierces the block of wood, the block exerts a force of friction on the bullet. As the bullet passes through the block, work is done against the resistive forces exerted on the bullet by the block. This results in the reduction of the bullet's kinetic energy. The bullet has a speed <em>v</em> when it emerges from the block.

If the block exerts a resistive force <em>F</em> on the bullet and the thickness of the block is <em>x</em> then, the work done by the resistive force is given by,

W=Fx

This is equal to the change in the bullet's kinetic energy.

W=Fx=\frac{1}{2} m(u^2-v^2)......(1)

If the thickness of the block is reduced by one-half, the bullet emerges out with a velocity v<em>₁.</em>

Assuming the same resistive forces to act on the bullet,

F(\frac{x}{2} )=\frac{1}{2} m(u^2-v_1^2)......(2)

Divide equation (2) by equation (1) and simplify for v<em>₁.</em>

\frac{\frac{Fx}{2} }{Fx} =\frac{(u^2-v_1^2)}{(u^2-v^2)} \\\frac{100^2-v_1^2}{100^2-10^2} =\frac{1}{2} \\v_1^2=5050\\v_1=71.06 m/s

Thus the speed of the bullet is 71 m/s


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3 years ago
Which is usually greater for a pair of surfaces, the coefficient of static friction or the coefficient of sliding friction? why
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Explanation :

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