Answer:
The mass m is 0.332 kg or 332 gm
Explanation:
Given
The platform is rotating with angular speed , 
Mass m is moving on platform in a circle with radius , 
Force sensor reading to which spring is attached , 
Now for the mass m to move in circle the required centripetal force is given by 
=>
Thus the mass m is 0.332 kg or 332 gm
<span>1 cal = 4,185 J
1 kcal = 1*10^3 cal
or
=1000 cal</span>
Answer:
a) x = ⅔ d
, b) the charge must be negative, c) Q
Explanation:
a) In this exercise the force is electric between the charges, we are asked that the system of the three charges is in equilibrium, we use Newton's second law. Balance is on the third load that we are placing
∑ F = 0
-F₁₂ + F₂₃ = 0
F₁₂ = F₂₃
let's replace the values
k Q Q / r₁₂² = k Q 4Q / r₂₃²
Q² / r₁₂² = 4 Q² / r₂₃²
suppose charge 3 is placed at point x
r₁₂ = x
r₂₃ = d-x
we substitute
1 / x² = 4 / (d-x) 2
1 / x = 2 / (d-x)
x = 2 (x-d)
x = 2x -2d
3x = 2d
x = ⅔ d
b) The sign of the charge must be negative, to have an attractive charge on the two initial charges
c) Q
