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bogdanovich [222]
4 years ago
15

Looking that following diagram of bar magnets, determine if the magnets will or will not connect (attract) and why.

Physics
1 answer:
vovangra [49]4 years ago
3 0

Answer: They will NOT connect because like poles are facing each other, and like poles repel each other.

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An x-ray has a wavelength of 4.18 Å. Calculate the energy (in J) of one photon of this radiation. Enter your answer in scientifi
Damm [24]

Answer:

E = 4.75 x 10⁻¹⁶ J

Explanation:

given,

wavelength of the x-ray , λ = 4.18 Å

Energy of photon = ?

we know

E = \dfrac{hc}{\lambda}

where h is the planks constant

          c is the speed of light

h = 6.626 x 10⁻³⁴ m² kg / s

c = 3 x 10⁸ m/s

now,

E = \dfrac{6.626\times 10^{-34}\times 3 \times 10^8}{4.18\times 10^{-10}}

E = 4.75 x 10⁻¹⁶ J

hence, the energy of the photon is equal to E = 4.75 x 10⁻¹⁶ J

4 0
4 years ago
Rubber is which of the following?
telo118 [61]

insulator.


it has no electrons free within it to move and to make an electric current

4 0
3 years ago
Record breaking low temperatures are associated with which air mass?
Papessa [141]

Answer:

Arctic Air masses

Explanation:

The Arctic Air masses are the world's most cold air masses. Specifically they are called Continental Arctic. Extremely cold and with very little moisture(extremely dry). These originate from north arctic region of 24 hour darkness that make the wind extremely cold and dry. The temperature in these regions are well below -50°C.

8 0
3 years ago
Which wave would have the greatest wave speed , a wave from a vibrating piano string in an auditorium or a sound wave created by
fenix001 [56]
The one in the water would have a much greater speed than the one in the air since energy is transmitted better and faster in liquid than gas.
7 0
4 years ago
Read 2 more answers
Suppose you wish to fabricate a uniform wire from a mass m of a metal with density rhom and resistivity rho. If the wire is to h
slamgirl [31]

Answer:

Explanation:

Resistivity and resistance are proportional and depends of the length and the cross-sectional area of the wire:

R=\frac{L}{A}\rho

furthermore, the density is the mass divided by the volume, and the volume can be written as the area multiplyed by the length:

\rho_m=\frac{m}{A*L}

Now you have tw equations and two variables, so you can solve for each of them.

first, solve for A in both equations and replace them:

\frac{L}{R}\rho=\frac{m}{\rho_mL}

L^2=\frac{mR}{\rho_m \rho} \\L=

now replace this into any of the previous equiations:

R=\frac{\sqrt{\frac{mR}{\rho_m \rho} } \rho}{A} \\A=\sqrt{\frac{mR\rho^2}{\rho_m \rho R^2} }\\A=\sqrt{\frac{m\rho}{\rho_m R} }

If you assume the wire has circular cross-sectional area, then the area is:

A=\pi(\frac{d}{2} )^2

solving for d:

d=2\sqrt{\frac{A}{\pi} }

replacing A and simplifying:

d=2 \sqrt[4]{\frac{m\rho}{\rho_m R \pi^2} }

5 0
3 years ago
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