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svlad2 [7]
3 years ago
5

Tidal forces are gravitational forces exerted on different parts of a body by a second body. Their effects are particularly visi

ble on the earth's surface in the form of tides. To understand the origin of tidal forces, consider the earth-moon system to consist of two spherical bodies, each with a spherical mass distribution. Let re be the radius of the earth, m be the mass of the moon, and G be the gravitational constant.
(a) Let r denote the distance between the center of the earth and the center of the moon. What is the magnitude of the acceleration ae of the earth due to the gravitational pull of the moon? Express your answer in terms of G, m, and r.
(b) Since the gravitational force between two bodies decreases with distance, the acceleration a_near experienced by a unit mass located at the point on the earth's surface closest to the moon is slightly different from the acceleration a_far experienced by a unit mass located at the point on the earth's surface farthest from the moon. Give a general expression for the quantity a_near - a_far. Express your answer in terms of G, m, r, and re.
Physics
1 answer:
laiz [17]3 years ago
6 0

Answer:

Explanation:

radius of earth = re

mass of the noon = m

mass of the earth = E

distance between earth and moon = r

acceleration of earth ae

force on earth = GMm / r²

acceleration of the earth

ae = force / mass

= GMm / (r² x M )

= Gm / r²

b ) The point on the earth nearest to moon will be at a distance of r - re

a_near = Gm / ( r - re)²

The point farthest on the earth  to moon will be at a distance of r + re

a_ far = Gm / ( r + re )²

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Currents during lightning strikes can be up to 50000 A (or more!). We can model such a strike as a 47500 A vertical current perp
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Answer:

57 N

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3 years ago
The moment of inertia of a thin uniform rod of mass M and length L about an Axis perpendicular to the rod through its Centre is
sleet_krkn [62]

Answer:

I = I₀ + M(L/2)²

Explanation:

Given that the moment of inertia of a thin uniform rod of mass M and length L about an Axis perpendicular to the rod through its Centre is I₀.

The parallel axis theorem for moment of inertia states that the moment of inertia of a body about an axis passing through the centre of mass is equal to the sum of the moment of inertia of the body about an axis passing through the centre of mass and the product of mass and the square of the distance between the two axes.

The moment of inertia of the body about an axis passing through the centre of mass is given to be I₀

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Answer:

#See solution for details.

Explanation:

1.

Tools:stopwatch, \ meter \ stick, \ mass \ measuring \ scale , \ force \ measuring  \ device.

Experiment \ 1:Calculate the speed of the wave using the time,t it takes to travel along the rope. Rope's length,L is measured using the meter stick.

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