KE = ½m*v² = ½*1.0*[0.866*3E8]² = 3.375E16 J
<span>Etot = mc²/√[1 - (v/c)²] = 1.8E17 J</span>
Answer:
19m
Explanation:
we have proper length L = 100m
the speed of the train v = 0.95
the speed of light is given as = 3x10⁸
length of the tunnel is given as = 50 meters
we can solve for the lenght contraction as
LX√1-v²/c²
= 100 * √1-(0.95*3x10⁸)²/(3x10⁸ )
= 31.22 metres
the train would be well seen at
50 - 31.22
= 18.78
= this is approximately 19 metres
we conclude tht the trains ends clears the ends of the tunnel by 19 meters.
thank you!
Answer:
La ecuación de onda lineal para una función f(x, t) se escribe como:

Donde c es una constante que depende de la velocidad de propagación de la onda.
En este caso, tenemos:

Recordar que la derivada de la exponente es tal que:

Entonces las derivadas de f van a ser:




Entonces podemos reescribir la ecuación de onda como:


Ahora podemos simplemente definir c^2 = (w/k)^2 y vemos que la ecuación de onda se cumple.
Answer:

Explanation:
Average acceleration is found by dividing the change in acceleration by the time.

The shuttle bus has an acceleration of -2.4 meters per square second. It slows from 9.0 meters per second to rest, or 0 meters per second. Therefore:

Substitute the values into the formula.

Solve the numerator.

We want to solve for t, the time. We have to isolate the variable. Let's cross multiply.



t is being multiplied by -2.4. The inverse of multiplication is division, so divide both sides by -2.4



It takes <u>3.75 seconds.</u>