<h3>
Answer: Largest value is a = 9</h3>
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Work Shown:
b = 5
(2b)^2 = (2*5)^2 = 100
So we want the expression a^2+3b to be less than (2b)^2 = 100
We need to solve a^2 + 3b < 100 which turns into
a^2 + 3b < 100
a^2 + 3(5) < 100
a^2 + 15 < 100
after substituting in b = 5.
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Let's isolate 'a'
a^2 + 15 < 100
a^2 < 100-15
a^2 < 85
a < sqrt(85)
a < 9.2195
'a' is an integer, so we round down to the nearest whole number to get 
So the greatest integer possible for 'a' is a = 9.
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Check:
plug in a = 9 and b = 5
a^2 + 3b < 100
9^2 + 3(5) < 100
81 + 15 < 100
96 < 100 .... true statement
now try a = 10 and b = 5
a^2 + 3b < 100
10^2 + 3(5) < 100
100 + 15 < 100 ... you can probably already see the issue
115 < 100 ... this is false, so a = 10 doesn't work
First we should get the slope.
m=y2 -y1/x2-x1
=2-1/2-0
=1/2
y=m(x-x1) +y1
=1/2(x-0) +1
=1/2x+1
Steps:
2 1/3 * 3 = 7
14 * 3 = 42
42 divided by 7 = 6
6 * 8 = 48
So, Maggie is 48 feet under the summit (-48). Therefore, the correct answer is d.
Answer:
i believe it is (3,6) im not 100% sure though
Step-by-step explanation: