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Lerok [7]
3 years ago
13

In the graph, z is a complex number represented as a vector from the origin. What is the product of z and its conjugate?

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
7 0

Do you have a picture

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Line segment BC will be reflected over line m to form line segment BC. Which of the following statements must be true?
Len [333]

Answer:

<u>Option A</u>

Step-by-step explanation:

To reflect line segment BC over line m, BB' will be perpendicular to the line m

and line m bisector of BB'.

<u>So, the correct answer is option A</u>

A) Line m is the perpendicular bisector of line segment BB' and the line segment CC'

<u>Option b is wrong</u> , it is impossible for the line B'C' to be perpendicular to line BC. B'C' is the image of BC.

<u>Both option c and d is wrong</u> because the perpendicular distance from b to the line m not equal to the perpendicular distance from c to the line m.

7 0
3 years ago
Can someone help me 19 to 32
andreev551 [17]

Answer:

simple just divide it by finding the reciprocal for the second number

ex: 2/4=4/2

then multiply

Step-by-step explanation:

8 0
3 years ago
Someone please help<br> ????????
Zanzabum

Answer:

use the distance formula,

by using it, prove the adjacent sides of the quadrilateral DEFG

hence, DEFG would be a rhombus

8 0
3 years ago
Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 75.6 Mbp
olga55 [171]

Answer:

a) 59.98

b) 2.99

c) 2.99

d) Significantly High

Step-by-step explanation:

Part a)

Highest speed measured = x = 75.6 Mbps

Average/Mean speed = \overline{x} = 15.62 Mbps

Standard Deviation = s = 20.03 Mbps

We need to find the difference between carrier's highest data speed and the mean of all 50 data​ speeds i.e. x - \overline{x}

x - \overline{x} = 75.6 - 15.62 = 59.98 Mbps

Thus, the difference between​ carrier's highest data speed and the mean of all 50 data​ speeds is 59.98 Mbps

Part b)

In order to find how many standard deviations away is the difference found in previous part, we divide the difference by the value of standard deviation i.e.

\frac{59.98}{20.03}=2.99

This means, the difference is 2.99 standard deviations or in other words we can say, the Carrier's highest data speed is 2.99 standard deviations above the mean data speed.

Part c)

A z score tells us that how many standard deviations away is a value from the mean. We calculated the same in the previous part. Performing the same calculation in one step:

The formula for the z score is:

z=\frac{x-\overline{x}}{s}

Using the given values, we get:

z=\frac{75.6-15.62}{20.03}=2.99

Thus, the Carriers highest data is equivalent to a z score of 2.99

Part d)

The range of z scores which are neither significantly low nor significantly​ high is -2 to + 2. The z scores outside this range will be significant.

Since, the z score for carrier's highest data speed is 2.99 which is well outside the given range, i.e. greater than 2, we can conclude that the  carrier's highest data speed​ is significantly higher.

3 0
3 years ago
Cole jarred 8 liters of jam after 2 days. How much jam did Cole jar if he spent 5 days making jam? Assume the relationship is di
BaLLatris [955]
20 liters. If there’s 8 liters every 2 days, 8 divided by 2 is 4. 4x5 is 20 liters.
4 0
2 years ago
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