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Anettt [7]
2 years ago
9

Which theoretical probabilities are equal to 1/3? Check all that apply.

Mathematics
2 answers:
umka21 [38]2 years ago
8 0

Answer:

2nd 4th and 5th theoretical probabilities are equal to 1/3.

Step-by-step explanation:

If a dice with six faces, having numbers (1-6) on each face is being rolled.

We will use the formula

P=\frac{\text{favorable outcome}}{\text{total number of possible outcomes}}

(1) rolling an even number on the first roll.

Favorable outcome = 2,4,6 (3 numbers)

P=\frac{3}{6}=\frac{1}{2}

(2) Landing on a star space on the first roll.

Maximum numbers of stars to be reached in first roll = 2

P=\frac{2}{6}=\frac{1}{3}

(3) Landing at Cat Town on the first roll is not possible because it is at 9th place. and we can reach at 6 place on first roll only.

Therefore, P=\frac{0}{6} =0

(4) Not landing on a question mark or star on the first roll.

Only 1 and 2 place has not question mark or star out of 6 places.

Favorable outcome will be = 2 (1 and 2)

P=\frac{2}{6}=\frac{1}{3}

(5) Rolling a number greater than 4 on the first roll.

Favorable outcome = 2 ( 5 and 6)

P=\frac{2}{6}=\frac{1}{3}

Therefore, 2nd 4th and 5th theoretical probabilities are equal to 1/3.

solong [7]2 years ago
5 0

Answer:

Assuming your rolling a six sided die, then the answers should be all of these:

landing on a star space on the first roll

not landing on a question mark or star on the first roll

rolling a number greater than 4 on the first roll

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Find the coordinates of the point 7/10 of the way from A to B. a=(-3,-6) b=(12,4)
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Answer:

The coordinates of M are x = \frac{15}{2} and y = 1.

Step-by-step explanation:

Let be A = (-3,-6) and B = (12, 4) endpoints of segment AB and M a point located 7/10 the way from A to B. Vectorially, we get this formula:

\overrightarrow {AM} = \frac{7}{10}\cdot \overrightarrow {AB}

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By Linear Algebra we get the location of M:

\vec M = \vec A + \frac{7}{10}\cdot (\vec B - \vec A)

\vec M = \vec A +\frac{7}{10}\cdot \vec B - \frac{7}{10}\cdot \vec A

\vec M = \frac{3}{10}\cdot \vec A + \frac{7}{10}\cdot  \vec B

If we know that \vec A = (-3,-6) and \vec B = (12, 4), then:

\vec M = \frac{3}{10}\cdot (-3,-6)+\frac{7}{10}\cdot (12,4)

\vec M = \left(-\frac{9}{10},-\frac{9}{5}  \right)+\left(\frac{42}{5} ,\frac{14}{5} \right)

\vec M =\left(-\frac{9}{10}+\frac{42}{5} ,-\frac{9}{5}+\frac{14}{5}   \right)

\vec M = \left(\frac{15}{2} ,1\right)

The coordinates of M are x = \frac{15}{2} and y = 1.

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