We'll use standard labeling of right triangle ABC, C=90 degrees, legs a, b, hypotenuse c.
11.
Right triangle, cliff peak A, boat B, angle opposite cliff is B=28.9 deg. adjacent leg a=65.7 m, cliff height is leg b.
tan B = b/a
b = a tan B = 65.7 tan 28.9° = 36.3 m
12.
Similar story, boat at B, opposite b=3.5 m, rope c=12 m
sin B = b/c
B = arcsin b/c = arcsin (3.5/12) = 17.0°
13.
c=124 m, A=58°
sin A = a/c
a = c sin A = 124 sin 58 = 105.2 m
14.
That's a hypotenuse c=4-1.2 = 2.8 m to a height b=1.8m so
cos A = b/c
A = arccos b/c = arccos (1.8/2.8) = 50.0°
15.
Not a right triangle, an isosceles triangle. Half of it is a right triangle with hypotenuse one arm, c=9.8 cm and angle opposite half the base of B=62/2=31°. We're after d=2b:
sin B = b/c
b = c sin B
d = 2b = 2 c sin B = 2(9.8) sin 31 = 10.1 cm
Almost equilateral
The answer is 12 good luck;)
The answer is 2/4 I believe
Answer:
(6,—6)
Step-by-step explanation:
Draw the points on a table. The answer will be (6,—6)
Answer:
6 / 51
Step-by-step explanation:
It is false.
Reason:
The probability of picking a black card at first is:
26 / 52 = 1/2
There are now 25 black cards and 51 cards in total.
The probability of picking another black card, if there's no replacement is now:
25 / 51
Now, there are 24 black cards and 50 cards left in total.
The probability of picking a black card without replacement now becomes:
24 / 50 = 12 / 25
Hence, the probability of picking three black cards without replacement is:
1/2 * 25/51 * 12 / 25 = 300 / 2550
In simplest form, it is 6 / 51
