Answer:
The distance between B and lighthouse is 3.8688 km
Step-by-step explanation:
Given:
The angle made from ship to lighthouse is 36.5 degrees
and that of point B is 73 degrees.
To Find:
Distance Between Point B and Lighthouse
Solution:
<em>Consider a triangle LAB(Refer the attachment )</em>
And Point C is on the line AB as A i.e. ship is sailing to B
So C is at 5 km from A.
Now In triangle LAC,
Using Trigonometry Functions as ,
tan(36.5)=LC/AC
LC=tan(36.5)*AC
=0.7399*5
=3.6998 km
Now In triangle LBC,
As,
Sin(73)=LC/LB
LB=LC/(Sin(73))
=3.6998/0.9563
=3.8688 km
LB=3.8688 km
Answer:
4.2 x 10⁶
Step-by-step explanation:
The problem says that there are 6x 10² times as many red blood cells as white blood cells. This means that you will need to multiply the given number of white blood cells, which is 7 x 10³ by 6x 10².
To do this, first you multiply the coefficients:
7 x 6 = 42
Next you combine the exponents of the 10s, because their bases are the same, we just add the exponents when you multiply them and copy the base:
10² x 10³ = 10⁵
So the result would be:
42 x 10⁵
However the following the form of scientific notation, you need to move the decimal one more time so that means you add one more to the exponent of 10.
4.2 x 10⁶