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2 years ago

X + 5y = 8 -x + 2y = -1 How is this solved?

1 answer:

8 0

Add both the equations together to eliminate x

x+5y=8
-x+2y=-1

7y=7
y=1

Now fill in y into the original equation

x+5(1)=8
x+5=8
x=3

Now you can check by filling x and y into the second equation.

-(3)+2(1)=-1
-3+2=-1
-1=-1

So your answer will be (3, 1)

Brainliest my answer if it helps you out?

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for a short time after a wave is created by wind the height of the wave can be modeled using y= a sin 2pit/T where a is the ampl

dangina [55]

Answer:

y = 4 sin(t/2 + 4π/3) − 2

Step-by-step explanation:

General form:

y = a sin(2π/T t)

Given a = 4 and T = 4π:

y = 4 sin(2π/(4π) t)

y = 4 sin(t/2)

Add horizontal shift of -4π/3 and vertical shift of -2:

y = 4 sin(t/2 − (-4π/3)) − 2

y = 4 sin(t/2 + 4π/3) − 2

6 0

3 years ago

X+9=24 how to solve for x

rodikova [14]

You can easily do just one step to get the value of x.

x + 9 =24 subtract 9 from both sides

x + 9 - 9 = 24 - 9

Simplify:

x = 15

I hope I helped you.

5 0

2 years ago

Read 2 more answers

This is the one!!!!!!!!!!!

sukhopar [10]

All you have to do is move the denominator on the other side, by multiplying.

a-10
------- = -9
20

multiply 20 x -9
= -180

then it becomes a-10=-180
+10 +10
a=-170

4 0

3 years ago

Read 2 more answers

Zachary is making dumplings. If he uses cup of dough for each dumpling, how

LekaFEV [45]

Answer:

11 cups of dough

Step-by-step explanation:

1 cup x 11 dumplings = 11 cups of dough needed

6 0

3 years ago

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Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

3 years ago