Answer:
Step-by-step explanation:
=\left(21\left(-3\right)-\left(-3\right)\cdot \:9\right)+\left(21\cdot \:9+\left(-3\right)\left(-3\right)\right)i
Answer:
look its really simple like if there is written the father age is two times than its son and its is also said sum of their age becomes 25 then
Step-by-step explanation:
solution,
let father and son age be x and y
2x =y ---------------(i)
x+y=25----------------(ii)
now,
putting the value of y in equation two we get,
x+(2x)=25
3x=25
x=25/3
x=8 yrs ( using round off)
again,
2x = y
2×8=y
16=y
therefore, father age is 16 and son age is 8
mark me brianliest
Wouldnt -128m^6 be the answer if there is no value for m?
Proving a relation for all natural numbers involves proving it for n = 1 and showing that it holds for n + 1 if it is assumed that it is true for any n.
The relation 2+4+6+...+2n = n^2+n has to be proved.
If n = 1, the right hand side is equal to 2*1 = 2 and the left hand side is equal to 1^1 + 1 = 1 + 1 = 2
Assume that the relation holds for any value of n.
2 + 4 + 6 + ... + 2n + 2(n+1) = n^2 + n + 2(n + 1)
= n^2 + n + 2n + 2
= n^2 + 2n + 1 + n + 1
= (n + 1)^2 + (n + 1)
This shows that the given relation is true for n = 1 and if it is assumed to be true for n it is also true for n + 1.
<span>By mathematical induction the relation is true for any value of n.</span>
