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3 years ago

How to solve the following question attached?

Mathematics

1 answer:

Mamont248 [21]3 years ago

4 0

Answer: AB=21.88 mm, BC=51.54 mm

Step-by-step explanation:

Given

$\angle A=67^{\circ}$

$AC=56\ mm$

The other two sides can find out using trigonometry

$\Rightarrow \sin 67^{\circ}=\dfrac{BC}{AC}\\\\\Rightarrow \sin 67^{\circ}=\dfrac{BC}{56}\\\\\Rightarrow BC=56\sin 67^{\circ}\\\Rightarrow BC=51.54\ mm$

Similarly, for AB

$\Rightarrow \cos 67^{\circ}=\dfrac{AB}{AC}\\\\\Rightarrow \cos 67^{\circ}=\dfrac{AB}{56}\\\\\Rightarrow AB=56\cos 67^{\circ}\\\Rightarrow AB=21.88\ mm$

Angle C is given by

$\angle C=90^{\circ}-67^{\circ}\\\angle C=23^{\circ}$

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Answer:

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Step-by-step explanation:

A sequence of Bernoulli trials composes the binomial distribution.

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$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

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The probability that a selected component is non-defective is 0.8

This means that $p = 0.8$

a) Three non-defective components in a batch of seven components.

This is P(X = 3) when n = 7. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{7,3}.(0.8)^{3}.(0.2)^{4} = 0.0287$

0.0287 = 2.87% probability that three non-defective components in a batch of seven components.

b) 8 non-defective components are drawn before the first defective component is chosen.

Now the order is important, so the we just multiply the probabilities.

8 non-defective, each with probability 0.8, and then a defective, with probability 0.2. So

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