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irina [24]
3 years ago
13

Plsss help me Brainlist!!

Mathematics
1 answer:
gulaghasi [49]3 years ago
5 0

I believe the answer to this is:

Mean: <u>8.7</u> minutes

Median: <u>9</u> minutes

Hope this helps! :D

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If the rate 130 miles per 2 hours is reduced to a unit rate, the result is
sammy [17]

Answer:

65 miles every 1 hour

Step-by-step explanation:

Unit rate is found once one of the units is 1. In this case we need to reduce the ratio so that it is 1 hour and we get a unit rate. We can do this by dividing both sided by 2 so that the hours are reduced to 1.

130=2

130/2=65                2/2=1

65=1

65 miles every hour

3 0
3 years ago
Find the common diffirence in the arithmetic sequence 1, 6/4, 10/4, 3...​
Temka [501]

Answer:

See explanation

Step-by-step explanation:

6/4 = 1.5

10/4 = 2.5

Therefore the sequence is 1, 1.5, 2.5, 3

So the common difference is either 0.5 or 1

8 0
2 years ago
Beth and Maria are going to the country fair. Admission costs $4 per persob for each day. They plan to go for 3 days. How much w
pshichka [43]
They will have to pay 24$ each for the both of them for all 4 days

8 0
3 years ago
Read 2 more answers
Which property best justifiies why the two expressions below are equivalent? 3(m+5)=3m+15
nadya68 [22]
The answer is the distributive property because it states that if you have a number multiplied by a quantity, you can just multiply that number by each of the terms in the quantity. For example, a(x+y)=ax+ay.

Hope this helps!
4 0
3 years ago
Daniela and Jack are hiking a steady incline. They use their GPS device to determine their elevation every 15 minutes. At 15 min
kow [346]

Answer:

h=40t+9700

where the elevation, h, is in feet and time, t, is in minutes.

Step-by-step explanation:

At the time, t_1=15 min, the elevation, h_1= 10,300 feet and

at the time t_2= 30 min, the elevation, h_2=10,900 feet.

As they are hiking a steady incline, so the change in the elevation with respect to time will be constant.

So, there will be a linear relationship between the elevation and the time.

Let h be the elevation at any time instant t, so the linear relation among these quantities is

h=mt+C_0\;\cdots(i)

where m is the rate of change of elevation with respect to time and C_0 is constant.

The change in the elevation, \Delta h=h_2-h_1= 10,900-10,300=600 feet.

and the change in time, \Delta t=t_2-1_1=30-15=15 min.

So, change in the elevation in unit time,

m=\frac{\Delat h}{\Delta t}=\frac{600}{15}=40 feet/min.

Now, from equation (i)

h=40t+C_0

As the elevation, h=h_1 at time t=t_1, so

10,300=40\times15+C_0

\Rightarrow C_0=9700

Hence, the required equation is

h=40t+9700

where the elevation, h, is in feet and time, t, is in minutes.

3 0
3 years ago
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