The length of B'C' in the rectangle A'B'C'D' = 9 units.
<u>Step-by-step explanation</u>:
step 1 :
Draw a rectangle with vertices ABCD in clockwise direction.
where, AB and DC are width of the rectangle ABCD.
AD and BC are length of the rectangle ABCD.
step 2 :
Now,
The length of the rectangle is AD = 5 units and
The width of the rectangle is AB = 3 units.
step 3 :
Draw another rectangle with vertices A'B'C'D' extended from vertices of the previous rectangle ABCD.
step 3 :
The length of the new rectangle is A'D' which is 4 units down from AD.
∴ The length of A'D' = length of AD + 4 units = 5+4 = 9 units
step 4 :
Since B'C' is also the length of the rectangle A'B'C'D', then the measure of B'C' is 9 units.
Answer:
297.5 in
Step-by-step explanation:
Area of triangle = Base times Height divided by 2.
Base=35
Height=17
So, 35 x 17 = 595
595/2=297.5
Answer:
<5 = 132°
<7 = 132°
<8 = 48°
Step-by-step explanation:
aAgle 2 and angle 5 are supplementary which means their sum is 180° so angle 5 is 180 - 48 = 32°
Angle 5 and angle 7 are congruent so their measures are equal 132°
Angle 8 and angle 2 are congruent and equal to each other as well
Answer:
a
Step-by-step explanation:
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