Answer:
8 possible combinations
Explanation:
In a diploid organism (2n), there are two sets of chromosomes in each cell. Each set of chromosome is contributed by each parent i.e one set of chromosome from the father and one set from the mother.
To determine the number of possible combinations in each gamete of a cell, we use the formula 2^n, where n = number of chromosomes in haploid gametes. In this case, the cell contains 3 pairs of chromosomes, meaning that each gamete will have 3 chromosomes. However, there will be 2³ = 8 possible combinations of chromosomes in each gametes.
Im not too sure what the answers you have are but cotton swab and put it in a bag if you write your own
Atoms are able to slide past one another in the liquid matter stage.
It is believed that a less massive star will age more slowly than a more massive star, despite the fact that massive stars have much more fuel. The reason that a more massive star will burn out quicker is because it takes a significant more amount of energy to keep the star burning due to the increased diameter of the star compared to the less massive star. A less massive star will use its fuel less quickly due to being smaller and having less mass to fuel.
The massive star burns its fuel at a greater rate than the less massive star.
Answer:
a dominant mutation
Explanation:
A monohybrid testcross is a cross-breeding experiment used to determine if an individual exhibiting a dominant phenotype is homo-zygous dominant or heterozygous for a particular phenotypic trait (in this case, wing length). In a monohybrid testcross, a 1:1 phenotypic ratio shows that the dominant parental phenotype was a heterozygote for a single gene that has complete dominance. Moreover, a 3:1 ratio in the F2 is expected of a cross between heterozygous F1 individuals, which means that 75% of individuals with short wings have the dominant allele that masks the expression of the long-wing trait (i.e. the recessive allele).
