Explanation:
(a) Molar mass of is 691.92 g/mol. And, there is 0.76 g of sodium monofluorophosphate () in 100 ml.
Molar mass of fluorine is 19 g/mol.
This means that in 691.92 g/mol there are 19 g/mol of fluorine is present. Hence, mass of fluorine present in 0.76 g is calculated as follows.
Mass of fluorine =
= 0.021 g
As, 1 g = 1000 mg. Hence, 0.021 g = 21 mg.
Therefore, mass of florine atoms in present was 21 mg.
(b) As we know that number of moles equal mass divided by molar mass.
Therefore, No. of moles of fluorine =
=
= 0.001 mol
Hence, according to mole concept in one mole there are atoms.
So, in 0.001 mole number of fluorine atoms will be calculated as follows.
atoms.
= atoms
Therefore, there are atoms of fluorine were present.
M(O)= 16 g/mol
M(H)=1 g/mol
m(O)/m(substance)
1) 16/17
2)16/18
3) 16/19
4) 32/34=16/17
1) and 4) give the same answers, and 16/17 are the greatest fraction, so greatest % oxygen by mass also.
The answers should be 1) and 4).
The answer to this is Hydrogen. <span />
Answer:
<em>The number of molecules in 16 grams of oxygen gas is 3.01*10^23, equal to half of Avogadro's number</em>
Explanation:
Answer:The compound created by calcium and chlorine is calcium chloride, and the formula for this compound is CaCl2 .
Explanation: