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IceJOKER [234]
3 years ago
12

Really strong acids and bases are found at the​

Chemistry
1 answer:
makkiz [27]3 years ago
4 0

Ends....................?

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Does Charles’s law hold when the gas becomes a liquid?
Mrac [35]

Answer:

no

Explanation:

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Identify the for of energy<br><br> (A)thermal<br> (B)kinetic<br> (C)chemical<br> (D)electrical
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<u>C Chemical Energy</u>

Explanation:

food gives us chemical energy which may be transformed to other later..

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3 years ago
Read 2 more answers
1. A chemical bond between metals and nonmetals; valence electrons are transferred ____.
Law Incorporation [45]

Answer:

1. Ionic bonding

2. Covalent bonding

3. Metallic bonding

Explanation:

Ionic bonding also referred to as electrovalent bonding is a kind of chemical bonding that involves the transfer of electrons between the valence shells of two elements with a large electronegativity difference usually a metal and a nonmetal.

For example an ionic bonding scenario might play out between a group one metal and a group seven halogen. While group one metals have one electron hindering their stability, group seven halogens need that one electron that could make them achieve this stability. It is this that causes them to come together in a way where the electron is transferred completely from the valence shell of the group 1 atom and accepted into the valence shell of the group 7 halogen.

Covalent bonding involves the sharing of electrons between atoms of comparable electronegativities. The electro negativity difference is not large enough to permit the total movement of the electrons and hence the electrons are then controlled by the nuclei of the two atoms

Between two metals, what we have is called the metallic bonding

7 0
3 years ago
How will an increase in wind speed affect soil erosion?
AnnyKZ [126]

Answer:

A. Soil erosion will increase.

7 0
3 years ago
An engine operates on a Carnot cycle that uses 1mole of an ideal gas as the
sattari [20]

Answer:

Step 1;

q = w = -0.52571 kJ, ΔS = 0.876 J/K

Step 2

q = 0, w = ΔU = -7.5 kJ, ΔH = -5.00574 kJ

Explanation:

The given parameters are;

P_i = 100 N·m

T_i = 327 K

P_f = 90 N·m

Step 1

For isothermal expansion, we have;

ΔU = ΔH = 0

w = n·R·T·ln(P_f/P_i) = 1 × 8.314 × 600.15 × ln(90/100) = -525.71

w ≈<em> -0.52571</em> kJ

At state 1, q = w = -0.52571 kJ

ΔS = -n·R·ln(P_f/P_i) = -1 × 8.314 × ln(90/100) ≈ 0.876

ΔS ≈ 0.876 J/K

Step 2

q = 0 for adiabatic process

ΔU = 25×(27 - 327) = -7,500

w = ΔU = <em>-7.5 kJ</em>

ΔH = ΔU + n·R·ΔT

ΔH = -7,500 + 8.3142 × 300 = -5,005.74

ΔH = ΔU = <em>-5.00574 kJ</em>

6 0
2 years ago
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