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IceJOKER [234]
3 years ago
12

Really strong acids and bases are found at the​

Chemistry
1 answer:
makkiz [27]3 years ago
4 0

Ends....................?

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Given 1 molecule of glutamate, how much atp can you form by oxidative phosphorylation?
hammer [34]

1 molecule of glutamate can form 7.6 ATP can be formed by oxidative phosphorylation .

<h3>What is oxidative Phosphorylation ?</h3>

In the process of oxidative phosphorylation, oxygen is consumed as electrons are transferred through the mitochondrial electron transport chain and ATP is produced.

The bulk of the ATP required for higher animals and plants to sustain life is produced by oxidative phosphorylation, which is also in charge of creating and preserving metabolic equilibrium.

The glutamate carrier recycles glutamate outside of mitochondria (T9). One aspartate and 7.6 ATP are made at the best return for each glutamine.

To learn more about oxidative phosphorylation, refer to the below link:

brainly.com/question/25765324

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5 0
1 year ago
Determine the enthalpy change for the decomposition of calcium carbonate. CaCO₃(s) --&gt; CaO(s) + CO₂(g) given the thermochemic
Hunter-Best [27]

Answer: c. 179 kJ/mol

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

Given:

Ca(OH)_2(s)\rightarrow CaO(s)+H_2O (l)   \Delta H_1= 65.2 kJ/mol     (1)

Ca(OH)_2(s)+CO_2(g)\rightarrow CaCO_3(s)+H_2O(l)    \Delta H_2= -113.8 kJ/mol   (2)

C(s)+O_2(g)\rightarrow CO_2(g)    \Delta H_3= -393.5 kJ/mol   (3)

2Ca(s)+O_2(g)\rightarrow 2CaO(s) \Delta H_4=-1270.2 kJ/mol    (4)

On subtracting eq (1) from eq (2) we have:

Ca(OH)_2(s)\rightarrow CaO(s)+H_2O(l) - Ca(OH)_2(s)+CO_2(g)\rightarrow CaCO_3(s)+H_2O(l)

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

\Delta H=-113.8-(65.2)kJ/mol=-179kJ/mol

Hence the enthalpy change for the raection is 179.0 kJ/mol.

6 0
3 years ago
Specific gravity is the density of an object compared to the density of .
Romashka [77]

Answer: option C. Water

Explanation:

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3 years ago
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Answer:

B

Explanation:

Noble gases are in group 18 (neon, argon, etc)

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3 years ago
When two metals touch in the mouth, a small shock is created. this is known as<br> a?
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 <span>When two metals touch in the mouth, a small shock is created. this is known as a </span>galvanic action
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