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IceJOKER [234]
3 years ago
12

Really strong acids and bases are found at the​

Chemistry
1 answer:
makkiz [27]3 years ago
4 0

Ends....................?

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An unknown diprotic acid (H2A) requires 44.391 mL of 0.111 M NaOH to completely neutralize a 0.58 g sample. Calculate the approx
Anna [14]

Answer:

M=235.42g/mol

Explanation:

Hello!

In this case, given this is an acid-base neutralization and we are considering a diprotic acid, we can write the following mole-mole relationship:

2n_{acid}=n_{base}

It means that the moles of acid can be computed given the volume and concentration of NaOH:

n_{acid}=\frac{M_{base}V_{base}}{2} =\frac{0.044391L*0.111mol/L}{2} \\\\n_{acid}=2.46x10^{-4}mol

It means that the approximate molar mass of the acid is:

M=\frac{m_{acid}}{n_{acid}} \\\\M=\frac{m_{acid}}{n_{acid}} =\frac{0.58g}{2.46x10^{-3}mol}\\\\M=235.42g/mol

Best regards!

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chegg 2. What pattern did you observe measuring cell voltages with a silver electrode versus with a platinum/H2 electrode There is a difference of -0.786 V in silver

<h3>What is cell voltages ?</h3>

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A 20-ohm resistor is the loud connected to a voltage source of 220 volts. what current will flow through the conductor
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