<span><span>KaAcid</span><span><span>1.0 * 109</span>Hydrobromic acidHBr</span><span><span>1.3 * 106</span>Hydrochloric acidHCl</span><span><span>1.0 * 103</span>Sulfuric acid<span>H2SO4</span></span><span><span>2.4 * 101</span>Nitric acid<span>HNO<span>3</span></span></span></span>
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Given the data from the question, the mass of arsenic that contains 1.23×10²⁰ atoms is 0.0153 g
<h3>Avogadro's hypothesis </h3>
6.02×10²³ atoms = 1 mole of arsenic
But
1 mole of arsenic = 75 g
Thus, we can say that:
6.02×10²³ atoms = 75 g of arsenic
<h3>How to determine the mass that contains 1.23×10²⁰ atoms</h3>
6.02×10²³ atoms = 75 g of arsenic
Therefore,
1.23×10²⁰ atoms = (1.23×10²⁰ × 75) / 6.02×10²³ atoms)
1.23×10²⁰ atoms = 0.0153 g of arsenic
Thus, 1.23×10²⁰ atoms is present in 0.0153 g of arsenic
Learn more about Avogadro's number:
brainly.com/question/26141731
