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3 years ago

In a circle graph, a section that represents 80% of the graph has a central angle measure of what? 72° 146° 288° 360°

Mathematics

2 answers:

gtnhenbr [62]3 years ago

8 0

Answer:

Step-by-step explanation:

80% · 360° (convert 80% to a decimal)

= 0.8 · 360° (then multiply 0.8 to 360°)

= 288°

Ratling [72]3 years ago

6 0

Answer:

288°

Step-by-step explanation:

80% of a circle is

80% of 360 degree

.80 *360

288

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I need help pls thank you and I'll send better pics

kakasveta [241]

$\begin{gathered} c)\text{ output = (input}\times\text{ input) }+\text{ 1} \\ d)\text{ output = input + 5} \end{gathered}$

Explanation:

$\begin{gathered} c)\text{ Change in input = 4 - 3 , 3 - 2, 2 -1 } \\ \text{change in input = 1 (it is constant )} \\ \text{The output depends on the input.} \end{gathered}$ $\begin{gathered} To\text{ get output 2: (1 }\times1\text{ )+ 1 = 1 +1 = 2} \\ To\text{ get output 5: (2}\times2)\text{ + 1 = 4 + 1 = 5} \\ To\text{ get output 10: (3}\times3)\text{ + 1 = 9 + 1 = 10} \\ To\text{ get output 17: (4}\times4)\text{ + 1 = 16 + 1 = 17} \\ To\text{ get output 26: (5}\times5)\text{ + 1 = 25 + 1 = 26} \end{gathered}$ $\begin{gathered} \text{Formula for the Process = (input}\times\text{ input) }+\text{ 1} \\ Process=(input)^2\text{ }+\text{ 1} \\ \text{output = (input}\times\text{ input) }+\text{ 1} \end{gathered}$

$\begin{gathered} d)\text{ rate of change = }\frac{change\text{ in output }}{\text{change in input}} \\ \text{rate of change = }\frac{-5-(-15)}{0-(-2)}\text{ = }\frac{10-(-5)}{3-0}\text{ = }\frac{15-10}{4-3} \\ \text{rate of change = }\frac{10}{2}\text{ = }\frac{15}{3}=\frac{5}{1} \\ \text{rate of change = 5} \end{gathered}$ $\text{output = input + 5}$

5 0

1 year ago

Jamie is riding a Ferris wheel that takes fifteen seconds for each complete revolution. The diameter of the wheel is 10 meters a

Agata [3.3K]

Answer:

The answers to the question is

(a) Jamie is gaining altitude at 1.676 m/s

(b) Jamie rising most rapidly at t = 15 s

At a rate of 2.094 m/s.

Step-by-step explanation:

(a) The time to make one complete revolution = period T = 15 seconds

Here will be required to develop the periodic motion equation thus

One complete revolution = 2π,

therefore the we have T = 2π/k = 15

Therefore k = 2π/15

The diameter = radius of the wheel = (diameter of wheel)/2 = 5

also we note that the center of the wheel is 6 m above ground

We write our equation in the form

y = $5*sin(\frac{2*\pi*t}{15} )+6$

When Jamie is 9 meters above the ground and rising we have

9 = $5*sin(\frac{2*\pi*t}{15} )+6$ or 3/5 = $sin(\frac{2*\pi*t}{15} )$ = 0.6

which gives sin⁻¹(0.6) = 0.643 = $\frac{2*\pi*t}{15}$

from where t = 1.536 s

Therefore Jamie is gaining altitude at

$\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi t}{15}) =$ 1.676 m/s.

(b) Jamie is rising most rapidly when the velocity curve is at the highest point, that is where the slope is zero

Therefore we differentiate the equation for the velocity again to get

$\frac{d^2y}{dx^2} = -5*(\frac{\pi *2}{15} )^2*sin(\frac{2\pi t}{15})$ =0, π, 2π

Therefore $-sin(\frac{2\pi t}{15} )$ = 0 whereby t = 0 or

$\frac{2\pi t}{15}$ = π and t = 7.5 s, at 2·π t = 15 s

Plugging the value of t into the velocity equation we have

$\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi t}{15}) =$ - 2/3π m/s which is decreasing

so we try at t = 15 s and we have $\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi *15}{15}) = \frac{2}{3} \pi$ m/s

Hence Jamie is rising most rapidly at t = 15 s

The maximum rate of Jamie's rise is 2/3π m/s or 2.094 m/s.

7 0

3 years ago

Calculate the infant mortality rate (per 1,000 live births) from the following data:

Feliz [49]

Answer:

ahsbbsnssisiskak sjsnsnaan

8 0

3 years ago

Dora is building the right square pyramid shown in the diagram.

saul85 [17]

Answer is 4 :) I hope it help you.

8 0

3 years ago

The distance between Joshua's home and school is 800 m. Joshua takes 5 min to walk

Fynjy0 [20]

Answer:

= 0.38 m/s

Step-by-step explanation:

▪Total distance = 800 m

5 min = 100 m

▪Remaining distance = 800 - 100 = 700 m

20 min = 700 m

▪Total time taken = 20 + 10 + 5 = 35 min

If 1 min = 60 sec

What about 35 min = ?

= 35 x 60

= 2100 sec

▪Average speed = TD ÷ TT

= 800 ÷ 2100

= 0.38 m/s

7 0

3 years ago