3 years ago

Solve this for me please and thank you

Mathematics

1 answer:

IRISSAK [1]3 years ago

8 0

I cant read youyr hand writting so i cant help because i need to read your hand writting

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Could someone explain thanks ive attached a picture

krek1111 [17]

We use a conjecture that says that the perpendicular bisector of a chord in a circle passes through the center of the circle.

The distances of the two bisectors are the same so the chord lengths are the same.

b = half of 22.5 = 11.25

The answer to your question is 11.25.

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Step-by-step explanation:

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Perform the following operations and write the answers in radical form. Part A:√7+√3+√98−√18 Part B:3√5−3√11+2√121−3√90

Sveta_85 [38]

Answer:

$\sqrt{7}+\sqrt{3}+4\sqrt{2}$
$3\sqrt{5}-3\sqrt{11}+22-9\sqrt{10}$

Step-by-step explanation:

Part A ;

$\sqrt{7} +\sqrt{3} +\sqrt{98} -\sqrt{18} \\\\\sqrt{98}=7\sqrt{2}\\\sqrt{18}=3\sqrt{2}\\\\=\sqrt{7}+\sqrt{3}+7\sqrt{2}-3\sqrt{2}\\\\\mathrm{Add\:similar\:elements:}\:7\sqrt{2}-3\sqrt{2}=4\sqrt{2}\\\\=\sqrt{7}+\sqrt{3}+4\sqrt{2}$

Part B ;

$3\sqrt{5} - 3\sqrt{11} + 2\sqrt{121} -3\sqrt{90} \\\\2\sqrt{121}=22\\3\sqrt{90}=9\sqrt{10}\\\\=3\sqrt{5}-3\sqrt{11}+22-9\sqrt{10}$

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4 years ago