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Zielflug [23.3K]
3 years ago
6

As of 2008 the longest car ever built was 30.5 meters long. A meter is a little longer than a yard. Estimate the length of this

car in feet.
Mathematics
1 answer:
dimaraw [331]3 years ago
6 0

The car would be about 90 ft

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Please Help ASAP!!!<br> Question in image below.
Luda [366]

Answer:

You know that XZ is 15 and the whole perimeter of the triangle is 50. WZ is going to be the same length as WX due to the lines saying that they are equal.

Your first step is to take 50-15=35, we did this because we already know the length of one side and can take that off from the whole.

The next step is to divide 35 by 2, because both sides are going to be the same length.

35/2=17.5

You final answer would be 17.5

Hope this helps ;)

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Lostsunrise [7]

Answer:

put it all in tiger algebra it will give you all of the answers

Step-by-step explanation:

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A self-serve car wash charges $5.34 to use its facilities, plus an additional $0.78 for each minute the customer is at the self-
erma4kov [3.2K]

T = 5.34 + 0.78m

T = 5.34 + 0.78 * 5

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Can someone help me?????
masha68 [24]
Answer: b
explanation: CD=AB since they are parallel meaning 33 = x+14 (solve to get y=19) and then AD=CB because they are also parallel meaning y=10
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3 years ago
A biologist is researching a newly discovered species of bacteria. At
lianna [129]

Answer:

  k ≈ 0.1733

Step-by-step explanation:

Using the numbers given, we find the multiplier of the population is 800/200 = 4 in 8 hours. This means the equation of growth can be written ...

  y = 200(4^(t/8))

When this is written in the form ...

  y = 200·e^(kt)

We can compare the two equations to see that ...

  4^(1/8) = e^k

Taking natural logarithms, we have ...

  1/8·ln(4) = k ≈ 0.1733

The growth rate k is approximately 0.1733.

_____

<em>Additional comment</em>

The comparison we were looking for was (4^(1/8))^t = (e^k)^t. Instead of "comparing" the equations, you could set them equal and solve for k.

  200(4^(t/8)) = 200e^(kt)

  4^(t/8) = e^(kt) . . . divide by 200

  t/8·ln(4) = kt·ln(e) . . . . take natural logs

  1/8·ln(4) = k . . . . . . use ln(e) = 1 and divide by t

6 0
2 years ago
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