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2 years ago

What is the division expression for 5/11

Mathematics

2 answers:

vampirchik [111]2 years ago

4 0

Answer:

In words: "Five divided by eleven" or as a numerical expression 5 ÷ 11

Step-by-step explanation:

Any fraction can be considered a division problem the top number (numerator) is divided by the bottom number (denominator).

If you put it into a calculator, you often get a long string of numbers after a decimal point. It may be easier to leave it as a fraction.

Another way to think of a fraction is how many things do you have: that's the numerator, and how many people get to share it-- the denominator. The fraction tells the amount of each person's share.

The denominator tells the size of the pieces-- in reverse! The larger the number, the smaller the piece!

Ivenika [448]2 years ago

3 0

Answer:

5 divide 11

Step-by-step explanation:

5 divide 11

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Answer:

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Step-by-step explanation:

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2 years ago

A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he

UkoKoshka [18]

Answer:

a) The minimum sample size is 601.

b) The minimum sample size is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

We dont know the true proportion, so we use $\pi = 0.5$ , which is when we are are going to need the largest sample size.

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

a. If a 95% confidence interval with a margin of error of no more than 0.04 is desired, give a close estimate of the minimum sample size that will guarantee that the desired margin of error is achieved. (Remember to round up any result, if necessary.)

This is n for which M = 0.04. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.04\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.04}$

$(\sqrt{n})^2 = (\frac{1.96*0.5}{0.04})^2$

$n = 600.25$

Rounding up

The minimum sample size is 601.

b. If a 95% confidence interval with a margin of error of no more than 0.02 is desired, give a close estimate of the minimum sample size necessary to achieve the desired margin of error.

Now we want n for which M = 0.02. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.02\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.02}$

$(\sqrt{n})^2 = (\frac{1.96*0.5}{0.02})^2$

$n = 2401$

The minimum sample size is 2401.

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3 years ago

What is the surface area of the triangular prism shown?

Lunna [17]

Answer:

The first step that we are going to do is to solve the area of the top rectangle. We are given a width of 15 cm and a length of 25 cm so we can just multiply them against each other to get the area.

$Area = l * w$

$Area = 25\ cm * 15\ cm$

$Area = 375\ cm^2$

The second side that we are going to solve for is the bottom rectangle. We are given a width of 12 cm and a length of 25 cm so lets just multiply them against each other to get the area.

$Area = l * w$

$Area = 25\ cm * 12\ cm$

$Area = 300\ cm^2$

The next area that we are going to determine is the back rectangle which has a width of 9 cm and a length of 25 cm so lets just multiply them against each other to get the area.

$Area = l * w$

$Area = 25\ cm * 9\ cm$

$Area = 225\ cm^2$

The final area that we have to determine are the side triangles. After determining the area of one triangle we will have to multiply it by 2 to get the area for both of the triangles. We are given a base of 12 cm and a height of 9 cm so lets just use the formula to find the area.

$Area = \frac{1}{2}* b*h$