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bixtya [17]
3 years ago
9

How do you use the slope to prove lines are parallel or perpendicular?

Mathematics
1 answer:
Murljashka [212]3 years ago
4 0
The slope for parallel lines are the same and the slope of perpendicular lines are negative reciprocals
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8fsquare + 4f - 60 <br> its an math equation can anyone plz gimme the answer
hammer [34]

Answer:

f = -3 , 5/2

Step-by-step explanation:

8f² + 4f - 60 = 0

Divide the entire equation by 4

2f² + f  - 15 = 0

Product = -30

Sum = 1

Factors = -5 , 6      {(-5)*6 = -30  and -5 +6 = 1}

2f² + f -15 = 0        {Rewrite the middle term using the factors}

2f² + 6f - 5f -15 = 0

2f(f + 3) - 5(f + 3) = 0

(f +3) (2f - 5) = 0

f +3  = 0    ; 2f -5 = 0

f = -3         ; 2f = 5

                    f = 5/2

6 0
2 years ago
What are the solutions of the equation 9x4 – 2x2 – 7 = 0? Use u substitution to solve. tions of the equation 9
skelet666 [1.2K]

Answer:

Step-by-step explanation:

Let u^2=x^4\\u = x^2

Subbing in:

9u^2-2u-7=0

a = 9, b = -2, c = -7

The product of a and c is the aboslute value of -63, so a*c = 63.  We need 2 factors of 63 that will add to give us -2.  The factors of 63 are {1, 63}, (3, 21}, {7, 9}.  It looks like the combination of -9 and +7 will work because -9 + 7 = -2.  Plug in accordingly:

9u^2-9u+7u-7=0

Group together in groups of 2:

(9u^2-9u)+(7u-7)=0

Now factor out what's common within each set of parenthesis:

9u(u-1)+7(u-1)=0

We know this combination "works" because the terms inside the parenthesis are identical.  We can now factor those out and what's left goes together in another set of parenthesis:

(u-1)(9u+7)=0

Remember that u=x^2

so we sub back in and continue to factor.  This was originally a fourth degree polynomial; that means we have 4 solutions.

(x^2-1)(9x^2+7)=0

The first two solutions are found withing the first set of parenthesis and the second two are found in other set of parenthesis.  Factoring (x^2-1) gives us that x = 1 and -1.  The other set is a bit more tricky.  If

9x^2+7=0 then

9x^2=-7 and

x^2=-\frac{7}{9}

You cannot take the square root of a negative number without allowing for the imaginary component, i, so we do that:

x=±\sqrt{-\frac{7}{9} }

which will simplify down to

x=±\frac{\sqrt{7} }{3}i

Those are the 4 solutions to the quartic equation.

5 0
3 years ago
Skf theatre bought a movie license for rs. 1,500 per week. the cost of keeping the stuff and the hall is rs. 20,000 per month. i
mart [117]

Answer:

<em>21500</em>

Step-by-step explanation:

21500 people would have to see the movie to recuperate their losses.

4 0
2 years ago
Find the slope intercept equation for the graph below pLz!!!
Komok [63]

Answer:

y=4/3x-1

Step-by-step explanation:

Slope-intercept form: y=mx+b where m is slope and b is y-intercept

We can see that the y-intercept is (0,-1)

The slope is (3-(-1))/(3-0)=4/3

8 0
2 years ago
Need help with this question
kumpel [21]

Answer:

B

Step-by-step explanation:

The problem wants you to PLUG IN x into the correct equation.

1) f(-1) means -1 equals x

f(3) means 3 equals x

For example g(9) means 9 = x and f(3/5) means 3/5 = x and so on.

2) Now that you know x equals two numbers -1 and 3 you have to plug them into a equation.

3) Which equation do you plug it in you may ask? You must plug in -1 into x^2 +3 BECAUSE the condition next to it says you can only plug in numbers to x^2+3 greater than or equal to -1 and less than 2. Therefore, you can plug in -1 to this equation.

-1^2 +3 = <u>4</u>

4) Now you have the number 3. Where do you think we should plug #3 into? Well you can plug it in to the first equation because the condition only allows numbers less then -1. the only option is the last one!!

1, for x >= 2 because 3 is certainly bigger than 2.

This means any number greater than or equal to 2 has to be 1.

SO OUR ANSWER IS 4 AND 1

6 0
3 years ago
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